CODEWITHSUNDEEP
msbuildmsbuild-task
Jose Bueno
Jose Bueno

Reputation: 126

MSBuild Annoyances (or blatant ignorance on my part)

In reworking our deployment process I moved over to using an MSBuild project in place of our existing batch files. All of the major elements are in place, and I was looking to cut out a step or two but ran into a snag.

I'm creating a property called OutputPath using the CombinePath task, and, while I can access it with no issues after it has been created I'm at a loss as for how to use it to my advantage. Consider:

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<MakeDir Directories="@(OutputFolder)" />
<MakeDir Directories="@(OutputFolder)\Foo" />
<MakeDir Directories="@(OutputFolder)\Bar" />

Commands 2 and 3 fail because I'm referencing an array and attempting to concatenate with a string. Creating a property and assigning it @(OutputFolder) simply results in another item group, not a property I can reference with the $ accessor. I do have an ugly workaround but I'd love to clear this up somewhat.

Thanks,

-Jose

Upvotes: 0

Views: 1817

Answers (2)

Jose Bueno
Jose Bueno

Reputation: 126

dOh! Definitely ignorance, used the wrong attribute on the Output element.

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" PropertyName="OutputFolder"/>
</CombinePath>

<MakeDir Directories="$(OutputFolder)" />
<MakeDir Directories="$(OutputFolder)\Foo" />
<MakeDir Directories="$(OutputFolder)\Bar" />

Upvotes: 1

justin.m.chase
justin.m.chase

Reputation: 13655

I'm not sure of the answer exactly but here is an idea:

<CombinePath BasePath ="$(DeployFolderRoot)" Paths ="$(DeployReleaseFolder)$(ReleaseFolderFormatted)" >
  <Output TaskParameter ="CombinedPaths" ItemName ="OutputFolder"/>
</CombinePath>

<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Foo" /> 
<OutputFolder Include="$(DeployFolderRoot)$(DeployReleaseFolder)$(ReleaseFolderFormatted)\Bar" />

<MakeDir Directories="@(OutputFolder)" />

Essentially, if you create OutputFolder items with the path they will just be appended to the list. This would have to be in an element btw, and you have to use Include="".

Upvotes: 3

Related Questions