CODEWITHSUNDEEP
bashdatetimedatetime
3dan
3dan

Reputation: 13

Converting date/time and generating offsets in bash script

I need a script to do some date/time conversion. It should take as an input a particular time. It should then generates a series of offsets, in both hour:minute form and number of milliseconds elapsed.

For 03:00, for example, it should give back 04:02:07 (3727000ms*) 05:04:14 (7454000ms), 06:06:21 etc...

How would I go about doing this as a bash script? Ideally it would work on both Mac OS X and Linux (Ubuntu or Debian).

Upvotes: 0

Views: 776

Answers (1)

Dennis Williamson
Dennis Williamson

Reputation: 360515

time2ms () {
    local time=$1 hour minute second
    hour=${time%%:*}
    minute=${time#$hour:}
    minute=${minute%:*}
    second=${time#$hour:$minute}
    second=${second/:}
    echo "$(( ( (10#${hour} * 60 * 60) + (10#${minute} * 60) + 10#${second} ) * 1000 ))"
}

ms2time () {
    local ms=$1 hour minute second
    ((second = ms / 1000 % 60))
    ((minute = ms / 1000 / 60 % 60))
    ((hour = ms / 1000 / 60 / 60))
    printf '%02d:%02d:%02d\n' "$hour" "${minute}" "${second}"
}

show_offsets () {
    local time=$1 interval=$2 time_ms interval_ms new_time
    time_ms=$(time2ms "$time")
    interval_ms=$(time2ms "$interval")
    new_time=$(ms2time $((time_ms + interval_ms)) )
    echo "$new_time (${interval_ms}ms)"
}

Demos:

$ show_offsets 03:00 1:02:07
04:02:07 (3727000ms)
$ show_offsets 03:00 2:04:14
05:04:14 (7454000ms)
$ show_offsets 03:00 3:06:21
06:06:21 (11181000ms)

Upvotes: 2

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