CODEWITHSUNDEEP
phpforms
Gattoo
Gattoo

Reputation: 3079

What makes PHP unset form variables?

My HTML code:

<form class="well" name="login" action="text.php" method="post" >
<input type="text" class="span3" id="username" name"username" placeholder="Enter your valid email">
<input type="text" class="span3" id="password" name"password" placeholder="Enter your password">
<button type="submit" class="btn" >Enzemble </button>
</form>
      <h2>New User? ... Register</h2>
        <form class="well" name="register" action="register.php" method="post" >
            <input type="text" class="span3" id="email" name="email" placeholder="Enter your valid email" onBlur="emailValidation()">
            <button type="submit" class="btn">Enter Enzemble!</button>
        </form>

The bottom form works fine.

The top code gives "undefined index" notice and does not read values of username and password in text.php The text.php code:

<?php
if (isset($email)) $email=$_POST["username"];
if (isset($password)) $password=$_POST["pasword"];
echo "username " . $email . "password " . $password;
?>

The error: Notice: Undefined index: pasword in /home/nitin/www/enzemble/text.php on line 8 Notice: Undefined variable: email in /home/nitin/www/enzemble/text.php on line 9 username password

I am not getting html form values in php. This is surprising. I am working on it for a long time. Please help.

Upvotes: 0

Views: 217

Answers (6)

Emil Vikstr&#246;m
Emil Vikstr&#246;m

Reputation: 91942

You have a syntax error in your HTML code. It's missing a = for the name attribute of the input fields:

<input type="text" class="span3" id="username" name"username" placeholder="Enter your valid email">
HERE ----------------------------------------------^

Upvotes: 0

dan-lee
dan-lee

Reputation: 14502

That's because you wrote pasword instead of password. Try it with

if (isset($password)) $password=$_POST["password"];

Anyway, you should check for $_POST['password'] instead just for $password

See register_globals:

This feature has been DEPRECATED as of PHP 5.3.0 and REMOVED as of PHP 5.4.0.

Upvotes: 4

Aurimas Ličkus
Aurimas Ličkus

Reputation: 10074

Because it's wrapped in another <form></form> wrap everything in one form.

Like:

  <form class="well" name="register" action="register.php" method="post" >
        <input type="text" class="span3" id="email" name="email" placeholder="Enter your valid email" onBlur="emailValidation()" />
        <input type="text" class="span3" id="username" name="username" placeholder="Enter your valid email" />
        <input type="text" class="span3" id="password" name="password" placeholder="Enter your password" />
        <button type="submit" class="btn">Enter Enzemble!</button>
    </form>

Edit: And update php script like Emil suggested

Upvotes: 0

Emil Vikstr&#246;m
Emil Vikstr&#246;m

Reputation: 91942

You are just checking if the variables $email and $password are set, but they aren't set yet, right? So either you meant to negate your checks:

if (!isset($email)) $email=$_POST["username"];
if (!isset($password)) $password=$_POST["password"];

Or you meant to check that the $_POST fields were set:

if (isset($_POST['email'])) $email=$_POST["username"];
if (isset($_POST['password'])) $password=$_POST["password"];

Upvotes: 2

nyson
nyson

Reputation: 1055

if (isset($password)) $password=$_POST["pasword"];

You're spelling password in $_POST["pasword"] with just one s.

Upvotes: 0

user680786
user680786

Reputation:

$password not exists yet, check $_POST["pasword"] in isset, not $password.

Upvotes: 0

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