CODEWITHSUNDEEP
androidyoutube-apiandroid-videoview
Beni
Beni

Reputation: 45

Why Videoview can't play a Youtube Video?

I'm trying to play a Youtube video from Youtube on some devices, but they return a dialog: "The video can't be played".

I've already read the Youtube API Documentation.

I've a VideoView and I set the video Uri as a url with a .3pg extension.

This is my code:

 VideoView videoView = (VideoView)this.findViewById(R.id.video); 
 MediaController mc = new MediaController(this); 
 videoView.setMediaController(mc);
 videoView.setVideoURI(Uri.parse("rtsp://v1.cache2.c.youtube.com/CigLENy73wIaHwmhXrOROaqgpBMYESARFEgGUgx1c2VyX3VwbG9hZHMM/0/0/0/video.3gp")); 
 videoView.requestFocus(); 
 videoView.start();

I've tried other videos and play correctly. What am I doing wrong?

Upvotes: 2

Views: 5525

Answers (3)

Amit
Amit

Reputation: 13394

If embedding video is not your explicit requirement, Why don't you simply start an intent with the Youtube video URL and let the OS handle the intent for you ? This is the simplest possible way to play video on android as far as I know. For example, 

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("Your youtube URL here"));
startActivity(intent);

For more information about Android Intents, see this link and vogella's tutorial

Upvotes: 1

K_Anas
K_Anas

Reputation: 31466

you need to launch an intent with a YouTube URL and let the OS handle it. That is, I don't think you can embed YouTube videos directly into your activities though I would love to be proven wrong.

Upvotes: 0

Vipul
Vipul

Reputation: 28103

Following snippet will hel you.

Basically you will need setOnPreparedListener

 try {

                final VideoView videoView =(VideoView)findViewById(R.id.videoView1);
                // Set video link (mp4 format )
                Uri video = Uri.parse(video_url);
                videoView.setVideoURI(video);
                videoView.setOnPreparedListener(new OnPreparedListener() {
                    public void onPrepared(MediaPlayer mp) {
                       progressDialog.dismiss();
                       videoView.start();
                    }
                });

             }catch(Exception e){
                 progressDialog.dismiss();
                 System.out.println("Video Play Error :"+e.getMessage());
             }

Upvotes: 0

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