CODEWITHSUNDEEP
javascriptjquery
Sasha
Sasha

Reputation: 8705

fadeOut -> fadeIn doesn't work properly

JS code:

var forma = $('form#mali_oglas'),
    pomoc = $('div[role=pomoc]'),
    div = $('.mali_oglas_pomoc'),
    input = forma.find('input, textarea');   

    input.on('click', function(){
        var name = $(':input:focus').attr("name")
        pomoc.fadeOut('fast', function(){            
            div.find("[data-pomoc='" + name + "']").fadeIn('slow');            
            console.log(name);
        });
    });

HTML code:

<div class="mali_oglas_pomoc">
    <div data-pomoc="name" role="pomoc">
        1Lorem ipsum dolor sit amet, consectetur adipiscing elit. Morbi pretium, urna nec varius sollicitudin, erat urna accumsan sapien, vel interdum enim risus id mi. Class aptent taciti sociosqu ad litora.
    </div>
    <div data-pomoc="body" role="pomoc">
        2Lorem ipsum dolor sit amet, consectetur adipiscing elit. Morbi pretium, urna nec varius sollicitudin, erat urna accumsan sapien, vel interdum enim risus id mi. Class aptent taciti sociosqu ad litora.
    </div>.....    
</div>

CSS for the div in question:

div[role="pomoc"] {position: absolute; top: 45px; right: 0;width: 250px; display: none}
div[role="pomoc"]:first-child {display: block}

It is working, but a bit strange. First it is applying display block to the targeted div, then fading it out and fading in. What is going on?

Link: http://jsfiddle.net/AY2B3/

Upvotes: 1

Views: 285

Answers (1)

veritasetratio
veritasetratio

Reputation: 611

The fadeOut callback is fired once for each completed animation. In your example, the callback gets executed multiple times because pomoc contains multiple elements. The strangeness is probably a visual artifact related to calling fadeIn multiple times on the same element.

Upvotes: 1

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