CODEWITHSUNDEEP
asp.net-mvcjqueryrazorasp.net-ajaxpartial-views
JMon
JMon

Reputation: 3447

Persist ID throughout ASP.NET MVC Views

Basically I have an Image Upload controller, that I am inserting in pages as follows :-

    <div id='imageList'>
    <h2>Upload Image(s)</h2>
    @{
        if (Model != null)
        {
            Html.RenderPartial("~/Views/File/ImageUpload.cshtml", new MvcCommons.ViewModels.ImageModel(Model.Project.ProjectID));
        }  
        else
        {
            Html.RenderPartial("~/Views/File/ImageUpload.cshtml", new MvcCommons.ViewModels.ImageModel(0));
        }
    }
</div>

So I am passing an ID to the ImageUpload, in this case the ProjectID, so that I can include it in my insert.

Now this is piece of code is populating an ImageModel(id), in my case its ProjectID :-

    public ImageModel(int projectId)
    {
        if (projectId > 0)
        {
            ProjectID = projectId;
            var imageList = unitOfWork.ImageRepository.Get(d => d.ItemID == projectId && d.PageID == 2);
            this.AddRange(imageList);
        }
    }

and this in turn leads to the ImageUploadView.cshtml :-

<table>
@if (Model != null)
{
  foreach (var item in Model)
  {
     <tr>
        <td>
          <img src= "@Url.Content("/Uploads/" + item.FileName)" />
        </td>
        <td>
          @Html.DisplayFor(modelItem => item.Description)
        </td>
    </tr>    
 }
}
</table>

@using (Html.BeginForm("Save", "File", new { ProjectID = Model.ProjectID }, 
       FormMethod.Post, new { enctype = "multipart/form-data" }))

{
    <input type="file" name="file" />
    <input type="submit" value="submit" /> <br />
    <input type="text" name="description" /> 
}

So far so good, however my problem is that the first time 

new { ProjectID = Model.ProjectID }

is correctly populated with the ProjectID, however, when I upload an image, the ProjectID is lost, and becomes zero. Is there a way I can persist the ProjectID for the second time?

Thansk for your help and time.

********* UPDATE ************************* After the upload, the Action is as follows inside the FileController :-

        public ActionResult Save(int ProjectID)
    {
        foreach (string name in Request.Files)
        {
            var file = Request.Files[name];

            string fileName = System.IO.Path.GetFileName(file.FileName);
            Image image = new Image(fileName, Request["description"]);

            ImageModel model = new ImageModel();
            model.Populate();
            model.Add(image, file);
        }
        return RedirectToAction("ImageUpload");
    }

Upvotes: 0

Views: 365

Answers (1)

VJAI
VJAI

Reputation: 32758

You can pass the projectId as a route value from the RedirectToAction. You should change the ImageUpload action to accept the projectId.

public ActionResult Save(int projectId)
{
  ....
  return RedirectToAction("ImageUpload", new { projectId = projectId });
}

public ActionResult ImageUpload(int projectId)
{
   var model = .. get the model from db based on projectId
   return View("view name", model);   
}

Upvotes: 1

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