CODEWITHSUNDEEP
phpregexstring
Maverick Johnson
Maverick Johnson

Reputation: 121

Searching a String using Regular Expression PHP

I have a string, I need to search this string and be able to assign the address details to a variable:

how it looks in the string:

infoone:"infoone"infotwo:"infotwo"address:"123 fake street pretend land"infothree:"infothree"infofour:"infofour" address:"345 fake street pretend land"infofive: "infofive"infosix: "infosix"

How would I use regular expressions to search through this string to lift only the data in the inverted commas after the word address,?

Note: I cannot target the phrase "123 fake street pretend land" as this is just an example used of what might be in the inverted commas.

Upvotes: 0

Views: 119

Answers (3)

Altaf Hussain
Altaf Hussain

Reputation: 1048

Use this regex

$str='infoone:"infoone"infotwo:"infotwo"address:"123 fake street pretend land"infothree:"infothree"infofour:"infofour" address:"345 fake street pretend land"infofive: "infofive"infosix: "infosix"';

preg_match_all("/address:\"(.*)\"/siU",$str,$out);
print_r($out[1]);

Upvotes: 1

buckley
buckley

Reputation: 14040

This is a fine regex

^address:"([^"]*)

This is it in php with the option so that ^ matches at the beginning of the line and we lift out group 1

preg_match_all('/^address:"([^"]*)/m', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[1];

Update 1

preg_match_all('/^address:"([^"]*)/m', $subject, $result, PREG_SET_ORDER);
for ($matchi = 0; $matchi < count($result); $matchi++) {
    for ($backrefi = 0; $backrefi < count($result[$matchi]); $backrefi++) {
        # Matched text = $result[$matchi][$backrefi];
    } 
}

Update 2

With the new sample input just leave at the ^ in the beginning so it becomes

address:"([^"]*)

Upvotes: 2

ash108
ash108

Reputation: 1761

Well, the regexp itself would be ^address:"(.*)"$.

Obviously, you'll need to add relevant preg_match() call.

Upvotes: 1

Related Questions