Itay Maman
Itay Maman

Reputation: 30733

Programmatically set a specific bean object - Spring DI

In my program I need to programmatically configure an ApplicationContext. Specifically, I have a reference to an instance of MyClass and I want to define it as a new bean called "xxyy".

public void f(MyClass mc, ApplicationContext ac) {
  // define mc as the "xxyy" bean on ac ???
  ...
  ...

  // Now retrieve that bean
  MyClass bean = (MyClass) ac.getBean("xxyy");

  // It should be the exact same object as mc
  Assert.assertSame(mc, bean); 
}

The BeanDefinition API let's me specify the class of the new bean, so it does not work for me since I want to specify the instance. I managed to find a solution but it took two additional factory beans which seems like too much code for such an eartly purpose.

Is there a standard API that addresses my needs?

Upvotes: 18

Views: 23401

Answers (2)

silmx
silmx

Reputation: 486

you can use this context:

GenericApplicationContext mockContext = new GenericApplicationContext();

which has a

mockContext.getBeanFactory().registerSingleton("name", reference);

and plug it in the real context

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(
            new String[] { "real-context.xml" }, mockContext);

and the classes are:

import org.springframework.context.support.ClassPathXmlApplicationContext;

import org.springframework.context.support.GenericApplicationContext;

Upvotes: 19

skaffman
skaffman

Reputation: 403611

You need to jump through a few hoops to do this. The first step is to obtain a reference to the context's underlying BeanFactory implementation. This is only possible if your context implements ConfigurableApplicationContext, which most of the standard ones do. You can then register your instance as a singleton in that bean factory:

ConfigurableApplicationContext configContext = (ConfigurableApplicationContext)appContext;
SingletonBeanRegistry beanRegistry = configContext.getBeanFactory();
beanRegistry.registerSingleton("xxyy", bean);

You can "insert" any object into the context like this.

Upvotes: 21

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