Reputation: 215
Concerning
floyds(int a[][100],int n).
What does 'a' and represent and what does each of the two dimensions of a represent?
What does 'n' represent?
I have a list of locations, with a list of connections between those locations and have computed the distance between those connections that are connect to each other. Now I need to find shortest path between any given two locations (floyd's) - but need to understand how to apply floyds(int a[][100],int n)
to my locations array, city dictionaries, and connection arrays.
FYI - Using objective C - iOS.
Upvotes: 0
Views: 1372
Reputation: 1
floyd-warshall(W) // W is the adjacent matrix representation of graph..
n=W.rows;
for k=1 to n
for i=1 to n
for j=1 to n
w[i][j]=min(W[i][j],W[i][k]+W[k][j]);
return W;
It's a dp-algorithm.At the k-th iteration here W[i][j] is the shortest path between i and j and the vertices of the shortest path(excluding i and j) are from the set {1,2,3...,k-1,k}.In min(W[i][j],W[i][k]+W[k][j]), W[i][j] is the computed shortest path between i and j at k-1-th iteration and here since the intermediate vertices are from the set {1,2...k-1},so this path does not include vertex k. In W[i][k]+W[k][j],we include vertex k in the path.whichever between the two is minimum is the shortest path at k-th iteration. Basically we check that whether we should include vertex k in the path or not.
Upvotes: 0
Reputation: 27994
n
is the number of nodes in the graph.
a
is an distance matrix of the graph. a[i][j]
is the cost (or distance) of the edge from node i to node j.
(Also read the definition of adjacency matrix if you need more help with the concept.)
Upvotes: 2
Reputation: 588
/* Assume a function edgeCost(i,j) which returns the cost of the edge from i to j
2 (infinity if there is none).
3 Also assume that n is the number of vertices and edgeCost(i,i) = 0
4 */
5
6 int path[][];
7 /* A 2-dimensional matrix. At each step in the algorithm, path[i][j] is the shortest path
8 from i to j using intermediate vertices (1..k−1). Each path[i][j] is initialized to
9 edgeCost(i,j).
10 */
12 procedure FloydWarshall ()
13 for k := 1 to n
14 for i := 1 to n
15 for j := 1 to n
16 path[i][j] = min ( path[i][j], path[i][k]+path[k][j] );
http://en.wikipedia.org/wiki/Floyd-Warshall
wiki is very good~~~
Upvotes: 1