Reputation: 8578
I am sorting a table. The fiddle can be found here.
CREATE TABLE test
(
field date NULL
);
INSERT INTO test VALUES
('2000-01-05'),
('2004-01-05'),
(NULL),
('2008-01-05');
SELECT * FROM test ORDER BY field DESC;
The results I get:
2008-01-05
2004-01-05
2000-01-05
(null)
However I need the results to be like this:
(null)
2008-01-05
2004-01-05
2000-01-05
So the NULL value is treated as if it is higher than any other value. Is it possible to do so?
Upvotes: 2
Views: 215
Reputation: 882146
Be wary of queries that invoke per-row functions, they rarely scale well.
That may not be a problem for smaller data sets but will be if they become large. That should be monitored by regularly performing tests on the queries. Database optimisation is only a set-and-forget operation if your data never changes (very rare).
Sometimes it's better to introduce an artificial primary sort column, such as with:
select 1 as art_id, mydate, col1, col2 from mytable where mydate is null
union all
select 2 as art_id, mydate, col1, col2 from mytable where mydate is not null
order by art_id, mydate desc
Then only use result_set["everything except art_id"]
in your programs.
By doing that, you don't introduce (possibly) slow per-row functions, instead you rely on fast index lookup on the mydate
column. And advanced execution engines can actually run these two queries concurrently, combining them once they're both finished.
Upvotes: 1
Reputation: 239764
Easiest is to add an extra sort condition first:
ORDER BY CASE WHEN field is null then 0 else 1 END,field DESC
Or, you can try setting it to the maximum of its datatype:
ORDER BY COALESCE(field,'99991231') DESC
COALESCE
/ISNULL
work fine, provided you don't have "real" data using that same maximum value. If you do, and you need to distinguish them, use the first form.
Upvotes: 4
Reputation: 300719
Use a 'end of time' marker to replace nulls:
SELECT * FROM test
ORDER BY ISNULL(field, '9999-01-01') DESC;
Upvotes: 4