CODEWITHSUNDEEP
iosjsongeocoding
PruitIgoe
PruitIgoe

Reputation: 6384

iOS geocoding data from google parsing json

I'm pulling some data from google maps but I can't seem to do anything with it. Here's my code:

- (void)connectionDidFinishLoading:(NSURLConnection *)theConnection  {

//do something with the data!
NSError *e = nil;
//parse the json data
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: receivedData options: NSJSONReadingMutableContainers error: &e];

//get the lat and long and put it into an array
locationData = [[NSMutableArray alloc] init];

NSLog(@"%@", [jsonArray objectAtIndex:0]);

}

if I log jsonArray.count I get 2, which seems right since google will return results and status at the top level. But if I try to get object 0 it crashes. If I try to do something like this it also crashes:

- (void)connectionDidFinishLoading:(NSURLConnection *)theConnection  {

//do something with the data!
NSError *e = nil;
//parse the json data
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData: receivedData options: NSJSONReadingMutableContainers error: &e];

//get the lat and long and put it into an array
locationData = [[NSMutableArray alloc] init];

for(NSDictionary* thisLocationDict in jsonArray) { 

    NSString* location = [thisLocationDict objectForKey:@"results"];
    [locationData addObject:location];
}
}

I use this code to get data from Twitter with no problems. The error I get in the console is I am trying to get an object of a string: 

-[__NSCFString objectForKey:]: unrecognized selector sent to instance 0x798a270

Here's the json google is sending me:

results = ( { "address_components" = ( { "long_name" = 2900; "short_name" = 2900; types = ( "street_number" ); }, { "long_name" = "Horizon Dr"; "short_name" = "Horizon Dr"; types = ( route ); }, { "long_name" = "King of Prussia"; "short_name" = "King of Prussia"; types = ( locality, political ); }, { "long_name" = "Upper Merion"; "short_name" = "Upper Merion"; types = ( "administrative_area_level_3", political ); }, { "long_name" = Montgomery; "short_name" = Montgomery; types = ( "administrative_area_level_2", political ); }, { "long_name" = Pennsylvania; "short_name" = PA; types = ( "administrative_area_level_1", political ); }, { "long_name" = "United States"; "short_name" = US; types = ( country, political ); }, { "long_name" = 19406; "short_name" = 19406; types = ( "postal_code" ); } ); "formatted_address" = "2900 Horizon Dr, King of Prussia, PA 19406, USA"; geometry = { location = { lat = "40.0896985"; lng = "-75.341717"; }; "location_type" = ROOFTOP; viewport = { northeast = { lat = "40.09104748029149"; lng = "-75.34036801970849"; }; southwest = { lat = "40.0883495197085"; lng = "-75.34306598029151"; }; }; }; types = ( "street_address" ); } ); status = OK; }

and the url I am passing:

http://maps.googleapis.com/maps/api/geocode/json?address=2900+Horizon+Drive+King+of+Prussia+,+PA&sensor=false

any idea what I am doing wrong?

Upvotes: 4

Views: 1276

Answers (1)

Diogo Grecco
Diogo Grecco

Reputation: 31

The difference from the data that you get from google is that it comes separate by keys, such as results, geometry, formatted_address...

You should do something like this:

NSError *error;

NSString *lookUpString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?address=%@&components=country:AU&sensor=false", self.searchBar.text];

lookUpString = [lookUpString stringByReplacingOccurrencesOfString:@" " withString:@"+"];

NSData *jsonResponse = [NSData dataWithContentsOfURL:[NSURL URLWithString:lookUpString]];

NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:jsonResponse options:kNilOptions error:&error];

self.locationArray = [[jsonDict valueForKey:@"results"] valueForKey:@"formatted_address"];

int total = self.locationArray.count;
NSLog(@"locationArray count: %d", self.locationArray.count);

for (int i = 0; i < total; i++)
{
    NSString *statusString = [jsonDict valueForKey:@"status"];
    NSLog(@"JSON Response Status:%@", statusString);

    NSLog(@"Address: %@", [self.locationArray objectAtIndex:i]);

}

Upvotes: 3

Related Questions