Reputation: 432
i=0
while read line
do
echo "i is --- $i"
#echo $line "\n"
if (( $i > 0 ))
then
$Eda_package=$(echo $line | awk '{print $1}')
$well_bias=$(echo $line | awk '{print $2}')
$biasmap=$(echo $line | awk '{print $3}')
$unified=$(echo $line | awk '{print $4}')
echo "eda pack --$Eda_package wellbias is --$well_bias biasmap is --$biasmap unified- -- $unified"
fi
i=$((i+1))
done < config.list
In the above bash program I get an error:
./script.sh: line 9: =EDA_7p0: command not found
How do I fix this?
Upvotes: 1
Views: 255
Reputation: 55
Let var1=1 and var2=2 now if you simply write $var2=$var1 then it will give you error that 2=1 command not found
When you initialize any variable you have to do it without $ with variable name on left side
Upvotes: 1
Reputation: 882646
Lines of the form:
$xyzzy=plugh
will have xyzzy
substituted before they're executed so that they look like:
=plugh
assuming they're not yet set. If they are set, you'll probably get different behaviour but still almost certainly not what you want.
You should change your lines from (for one example):
$Eda_package=$(echo $line | awk '{print $1}')
to:
Eda_package=$(echo $line | awk '{print $1}')
The $
is not part of the variable name, it's an indication that the following word is a variable that should be substituted.
Upvotes: 5