CODEWITHSUNDEEP
phpmysql
chasemb
chasemb

Reputation: 167

PHP - Mysql query: Display number of orders by day and store in variables

I have a table with this structure:

table name: customer_history

id| orders | order_date (timestamp) |  status    |  
--------------------------------------------------
 1|   1    | 2012-05-29 13:11:59    |  active    |
 2|   1    | 2012-05-29 13:11:59    |  active    |
 3|   1    | 2012-05-30 13:11:59    |  canceled  |
 4|   1    | 2012-05-31 13:11:59    |  trialing  |

I need to query the db and count the number of total orders, where status != canceled, for each day, going back one calendar month, and assign a unique variable to each daily total.

Yesterday's order total would be something like $day-1, two days ago $day-2, etc.

EDIT Answer below.

$query = "SELECT 
            COUNT(*) AS number, 
            DATE(order_date) AS order_day 
        FROM 
            customer_history
        WHERE 
            status <> 'canceled' 
        GROUP BY 
            order_day 
        ORDER BY 
            order_date 
        DESC
        LIMIT 31";

$result = mysql_query($query) or die(mysql_error());

$i = 1;
$days = array();

while($row = mysql_fetch_assoc($result)) {

      $days[$i] = $row;
      $i++;
}

echo $days[1]['number'];
echo $days[2]['number'];
echo $days[3]['number'];
echo $days[4]['number'];
echo $days[5]['number'];
echo $days[6]['number'];

Upvotes: 1

Views: 1749

Answers (2)

Sherlock
Sherlock

Reputation: 7597

SELECT COUNT(*) AS number, DATE(order_date) AS order_day FROM orders WHERE status <> 'canceled' GROUP BY order_day ORDER BY order_date DESC LIMIT 31

Then just loop over the results. First one is the current day, second is yesterday, third is day before yesterday, etc.

EDIT

Including loop/variables:

    <?php

$query = "SELECT 
                COUNT(*) AS number, 
                DATE(order_date) AS order_day 
            FROM 
                orders 
            WHERE 
                status <> 'canceled' 
            GROUP BY 
                order_day 
            ORDER BY 
                order_date 
            DESC
            LIMIT 31";

    $result = mysql_query($query);

    $i = 1;
    $days = array();

    while($row = mysql_fetch_assoc($query)
    {
        $days[$i] = $row;
        $i++;

    }

    ?>

echo $days[1]['number'] gives you the number of orders for today, $days[2]['number'] for yesterday, etc. You can output the actual date by echoing $days[x]['order_day'].

Upvotes: 1

Query Master
Query Master

Reputation: 7097

Try this Query with GROUP BY order_date

SELECT COUNT(*) AS number, DATE(order_date) AS order_day
FROM orders WHERE status != 'canceled' 
GROUP BY order_date ORDER BY order_date DESC

Upvotes: 1

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