CODEWITHSUNDEEP
carrays
Hamoudaq
Hamoudaq

Reputation: 1498

How to check an array for non-zero values (elements)

I am wondering how to approach writing a function that would return whether there were at least three values not equal to 0. I've searched for similar problems, but I couldn't find any effective solution. In order to explain my problem, here is an example:

I have an array which contains these elements: [1,0,2,0,4,0,0,3,0,0]. I want to check if there are at least 3 elements not equal to zero.

My code would return 1 if there are at least 3 elements != 0 , or return 0 if there are less than 3 elements !=0.

So in my example it should return 1.

Upvotes: 4

Views: 25395

Answers (3)

Hamoudaq
Hamoudaq

Reputation: 1498

i'd like to share my solution

int check(){
    int arr[10]= [1,0,2,0,4,0,0,3,0,0];
    int total=0;
    for(int i=0;i<=10;i++){
        total+=arr[i];
     }
    return total;
}

thank you guys for trying to solve my problem <3

Upvotes: -1

mohit
mohit

Reputation: 6044

int non_zero(int a[], int lim) {  
    int i, count;
    count = 0;
    for (i = 0; i < lim && count < 3; i++)
        if (a[i] != 0)
            count++;
    return count == 3 ? 1 : 0;
}

Upvotes: 1

tskuzzy
tskuzzy

Reputation: 36446

Count the number of elements not equal to zero. If less than three, return false, else return true.

In order to obtain the count, loop through the contents of the array using a for loop and then use an if statement to test if the element is zero.

Upvotes: 5

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