Reputation: 187
Can anyone plese advice how I can have dynamic HREF attribute in the place of ʜᴛᴛᴘ://abc.com by XSLT in following code snippet?
<xsl:for-each select="MenuItems/mainmenu">
<a href="ʜᴛᴛᴘ://abc.com">
<span><xsl:value-of select="menuName"/></span>
</a>
</xsl:for-each>
sample xml
<MenuItems>
<mainmenu>
<menuID>1</menuID>
<menuName>Home</menuName>
<menuLink>http://aaa.com</menuLink>
<subMenuList>
<menuID>2</menuID>
<menuName>Home</menuName>
<menuLink>http://a1.com</menuLink>
</subMenuList>
<subMenuList>
<menuID>3</menuID>
<menuName>List of RCCs</menuName>
<menuLink>http://a2.com</menuLink>
</subMenuList>
<subMenuList>
<menuID>4</menuID>
<menuName>Turnover Workout</menuName>
<menuLink>http://a3.com</menuLink>
</subMenuList>
</mainmenu>
<MenuItems>
Upvotes: 1
Views: 5065
Reputation: 163262
Use an attribute value template:
<a href="{menuLink}">
<span><xsl:value-of select="menuName"/></span>
</a>
Upvotes: 1
Reputation: 20710
If I understand correctly, you are looking for the <xsl:attribute>
element:
<a>
<xsl:attribute name="href"><xsl:value-of select="menuLink"/></xsl:attribute>
<span><xsl:value-of select="menuName"/></span>
</a>
Upvotes: 3