Reputation: 341
First let me say I have read this useful article thoroughly and am using the SafeThread class from CodeProject. I get the same result whether using Thread or SafeThread.
I have reduced my problem down to an app consisting of two forms each with one button. The main program displays a form. When you click that button, a new thread starts which displays a second form. When you click the button on the second form, internally it just does "throw new Exception()"
When I run this under VS2008, I see "Exception in DoRun()".
When I run outside of VS2008, I get a dialog box "Unhandled exception has occurred in your application. If you click continue, the application ...."
I have tried setting legacyUnhandledExceptionPolicy in the app.config to both 1 and 0.
What do I need to do to capture the exception thrown in my second form, when not running under VS2008?
Here's my Program.cs
static class Program
{
[STAThread]
static void Main()
{
Application.ThreadException += new ThreadExceptionEventHandler (Application_ThreadException);
Application.SetUnhandledExceptionMode (UnhandledExceptionMode.CatchException);
AppDomain.CurrentDomain.UnhandledException += new UnhandledExceptionEventHandler(CurrentDomain_UnhandledException);
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
try
{
Application.Run(new Form1());
}
catch(Exception ex)
{
MessageBox.Show("Main exception");
}
}
static void CurrentDomain_UnhandledException(object sender, UnhandledExceptionEventArgs e)
{
MessageBox.Show("CurrentDomain_UnhandledException");
}
static void Application_ThreadException(object sender, ThreadExceptionEventArgs e)
{
MessageBox.Show("Application_ThreadException");
}
}
Here's Form1:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
SafeThread t = new SafeThread(new SimpleDelegate(ThreadMain));
try
{
t.ShouldReportThreadAbort = true;
t.ThreadException += new ThreadThrewExceptionHandler(t_ThreadException);
t.ThreadCompleted += new ThreadCompletedHandler(t_ThreadCompleted);
t.Start();
}
catch(Exception ex)
{
MessageBox.Show(string.Format("Caught externally! {0}", ex.Message));
}
}
void t_ThreadCompleted(SafeThread thrd, bool hadException, Exception ex)
{
MessageBox.Show("t_ThreadCompleted");
}
void t_ThreadException(SafeThread thrd, Exception ex)
{
MessageBox.Show(string.Format("Caught in safe thread! {0}", ex.Message));
}
void ThreadMain()
{
try
{
DoRun();
}
catch (Exception ex)
{
MessageBox.Show(string.Format("Caught! {0}", ex.Message));
}
}
private void DoRun()
{
try
{
Form2 f = new Form2();
f.Show();
while (!f.IsClosed)
{
Thread.Sleep(1);
Application.DoEvents();
}
}
catch(Exception ex)
{
MessageBox.Show("Exception in DoRun()");
}
}
}
And here is Form2:
public partial class Form2 : Form
{
public bool IsClosed { get; private set; }
public Form2()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
throw new Exception("INTERNAL EXCEPTION");
}
protected override void OnClosed(EventArgs e)
{
IsClosed = true;
}
}
Upvotes: 3
Views: 13543
Reputation: 4196
If you really want your second Form opened on a separate UI thread (not as ShowDialog()
) to catch the exception and send it to your Application_ThreadException
method, you need to ensure that the second thread is also set to CatchException
and you need to subscribe to the Application.ThreadException
on that thread, too. Both of these are thread-specific (and a bit quirky).
You can set the default "unhandled exception mode" by calling:
Application.SetUnhandledExceptionMode(UnhandledExceptionMode.CatchException, false);
This sets the application-wide mode to CatchException
for any UI thread you create. (But this call will fail when running in the Visual Studio debugger and some other cases.) Or, your new UI thread can set its own mode with the usual call (same as passing true to this overload).
Either way, the new UI thread also needs to subscribe to the Application.ThreadException
event itself, because the subscriber is stored in a [ThreadStatic] variable.
Application.ThreadException += Program.Application_ThreadException;
Or it could use a separate handler instead of routing to the same one, if that's helpful.
I'm not sure how this might intersect with using SafeThread
to accomplish it, but I think if this is done correctly for the second UI thread it wouldn't be necessary to use SafeThread
. It's much like you'd do it on your main UI thread.
Also see my answer to this question for more on the quirks of this stuff.
Upvotes: 3
Reputation: 30303
Instead of this line:
Application.SetUnhandledExceptionMode(UnhandledExceptionMode.CatchException);
You need this:
#if DEBUG
Application.SetUnhandledExceptionMode(UnhandledExceptionMode.CatchException);
#else
Application.SetUnhandledExceptionMode(UnhandledExceptionMode.ThrowException);
#endif
This way, when you run the program in Visual Studio under Debug mode, Visual Studio will trap the exceptions when they happen so you can debug them at the point they occur. When you run your program in release mode, the exceptions will be caught by the handler for Application.ThreadException
or the handler for the AppDomain
.
This works perfectly in my program. I got tired of getting emails with the "Unhandled exception has occurred in your application..." box, so I implemented a universal form with a text box that allows me to dump specific information that I use to debug the problem.
Upvotes: 1
Reputation: 13655
1.) I would recommend using the BackgroundWorker instead of separate threads like this. Your worker will catch exceptions and pass them along as a parameter to the complete handler.
2.) I would use ShowDialog() instead of Show() when displaying the second form, this will block the DoRun() at that method call and exceptions should then be caught by your surrounding try / catch (or the BackgroundWorker if you're using that instead).
I think the problem comes that since you're calling Show() you're essentially dispatching that call onto the Invoker, which ends up being queued in the UI thread. So when an exception happens there is nothing higher up the callstack to catch it. I believe calling ShowDialog() will fix this (and also allow you to drop that nasty for loop).
Something like this:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
// NOTE: I forget the event / method names, these are probably a little wrong.
BackgroundWorker worker = new BackgroundWorker();
worker.DoWork += (o, e) =>
{
Form2 f = new Form2();
e.Result = f.ShowDialog();
};
worker.DoWorkComplete += (o, e) =>
{
if(e.Error != null)
MessageBox.Show(string.Format("Caught Error: {0}", ex.Message));
// else success!
// use e.Result to figure out the dialog closed result.
};
worker.DoWorkAsync();
}
}
Actually, now that I think about it, it's sort of weird to be opening a dialog from a background thread but I think this will still work.
Upvotes: 2
Reputation: 59645
The problem seems to be caused by the button event handler. If you throw an exception in DoRun()
- maybe after Form.Show()
- the exception will be caught as exspected no matter if you are runing inside Visual Studio or not.
Interesting is, that the behavior depends on whether the debugger is attached to the process, or not. Starting outside of Visual Studio and attaching the debugger later prevents the send feedback message box, detaching makes it occur again. The same from within Visual Studio - "Start without debugging" cause the send feedback message box to occur.
So I quickly steped through the framework source code after the exception occured in the button event handler and had a rough look at it - the message pump, the controls, and probably a lot of other code do a lot of stuff there. Because WinForms are just wrapper around native controls I assume that for some reason the exception is not returned to the same point or thread depending on whether a debugger is attached or not - maybe something goes wrong when the exception is passed across thread or process boundaries or something like that.
Upvotes: 0
Reputation: 39480
Have you tried putting a try / catch block in your main method?
Upvotes: 0