CODEWITHSUNDEEP
javaprotectedsuperinheritance
alaska
alaska

Reputation: 151

super protected java

A question about inheritance in java... 

class Base {
    private int val = 10;
}

class Derive extends Base{
    public void setVal(int value) {
        super.val = value;
    }
}

Since we can change the private field in super class using super keyword in the subclass, why should we use protected to declare fields in super class?

Upvotes: 0

Views: 367

Answers (3)

saurabh kumar
saurabh kumar

Reputation: 164

super is an reference variable which is used to call parents constructor.

Upvotes: 0

saurabh kumar
saurabh kumar

Reputation: 164

Check your code you can never access private out side the class even if you have inherited that class.

Upvotes: 0

Jon Skeet
Jon Skeet

Reputation: 1499770

You can't do that. The code you've given doesn't compile, unless Derive is declared as a nested class within Base (which is a pretty rare case).

You should be getting an error like this:

error: val has private access in Base

Upvotes: 4

Related Questions