CODEWITHSUNDEEP
phpdatetimedate
CyberJunkie
CyberJunkie

Reputation: 22674

php date_diff in hours

How is it possible to make the code below convert days in hours?

$timestart = date_create('02/11/2011' . $row->timestart); //$row->timestart returns time in 00:00:00 format
$timestop = date_create('02/11/2011' . $row->timestop); //$row->timestop returns time in 00:00:00 format

date_add($timestop, date_interval_create_from_date_string('2 days')); //add 2 days

$date_diff = date_diff($timestart, $timestop);

echo "Timespan: ";
echo $date_diff->format('%h hours');
echo "<br />";

How can I get the hours:minutes:seconds elapsed? I'm trying to stay with the date_diff function.

Upvotes: 0

Views: 10568

Answers (2)

Madara&#39;s Ghost
Madara&#39;s Ghost

Reputation: 174957

The DateInterval object, returned by date_diff stores each period of time separately, seconds, minutes, hours, days, months and years.

Since the difference is 2 days, the hours property is 0, which is what you get.

Upvotes: 1

raina77ow
raina77ow

Reputation: 106385

The result of date_diff() is an object of DateInterval class. Such object has a very useful property - $days: it's total number of days between the starting and the ending dates. Besides, it stores (as its public properties) the difference in hours, minutes and seconds.

So, I suppose, what you need is just extract values of these properties from $date_diff variable, then add 24*$days to the hours number. ) All this can be wrapped into a simple function:

function hms_date_diff(DateInterval $date_diff) {
  $total_days = $date_diff->days;
  $hours      = $date_diff->h;
  if ($total_days !== FALSE) {
    $hours += 24 * $total_days;
  }
  $minutes    = $date_diff->i;
  $seconds    = $date_diff->s;
  return sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);
}

As for DateDiff::format, the doc says...

The DateInterval::format() method does not recalculate carry over points in time strings nor in date segments.

Upvotes: 6

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