CODEWITHSUNDEEP
assemblyx86x86-16
Ojaghi
Ojaghi

Reputation: 1

Effective and relative address in 8086

im not sure in 8086 that i understand it right but i want to share it CS,Ds,ss,es are stores the pointer to segment in the memory cs:ip => say the relative address of current instruction and if we want to calculate the physical address(or effective) address we just adding a 0h to end of the code segment and add it with ip ds:bx say the relative address of data and if we want to calculate the physical address(or effective) address we just adding a 0h to end of the Data segment and add it with bx

am i understanding right??!!

Upvotes: 0

Views: 1971

Answers (1)

Jens Björnhager
Jens Björnhager

Reputation: 5648

Yes, in other words, multiply the segment by 16/shift it left by four, and add the offset to it.

Upvotes: 1

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