CODEWITHSUNDEEP
asp.net-mvc-3
Dave
Dave

Reputation: 5029

In partial view: "The model item passed into the dictionary is of type"

I lack understanding of some basic MVC concepts, despite all my searching.

I created an MVC project in Visual Studio, which contains the partial view _LogOnPartial.shtml. I just want to access information within the view pertaining to the user, to put in a user dropdown menu. When I try to put this at the top of the partial view cshtml page I get the above error:

@model MyProject_MVC.Models.UserRepository

When I try this I also get an error:

@Html.Partial("_LogOnPartial", MyProject_MVC.Models.UserRepository)

'MyProject_MVC.Models.UserRepository' is a 'type', which is not valid in the given context

Upvotes: 2

Views: 3308

Answers (2)

Ufuk Hacıoğulları
Ufuk Hacıoğulları

Reputation: 38468

You have to provide an instance of MyProject_MVC.Models.UserRepository to the partial view. _LogOnPartial is strongly-typed to that type. It lets you access its public members at compile time and decide how you can display it in your view.

If you want to use your own type in that view, first you have to change the type that is strongly-typed to it.

@model MyProject_MVC.Models.UserRepository

Then you have to create an instance of that type in your action method and pass it to the view as the model or a property of the model.

public ActionResult LogOn()
{
    return View(new UserRepository());
}

Now you can access this instance as Model object in your view.

@Html.Partial("_LogOnPartial", Model);

Upvotes: 2

user1047100
user1047100

Reputation:

@model _LogOnPartial.Models.UserRepository should probably be: @model MyProject_MVC.Models.UserRepository

and for the last part, you have to provide and instance of the type UserRepository as the second parameter, not the type itself.

Upvotes: 2

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