Reputation: 524
I have this table structure on a SQL Server 2008 R2 database:
CREATE TABLE FormTest
(
clientid char(10),
DateSelected date,
A int,
B int,
C int
)
I filled the table FormTest with the following information
clientid DateSelected A B C
x1 2006-06-09 65150 4921 1
x2 2006-05-05 155926 69092 1
x3 2006-01-20 95603 156892 1
x4 2006-01-20 30704 164741 1
x4 2006-02-03 65150 174834 1
x5 2006-04-28 59629 4921 1
x6 2006-01-27 30704 162356 1
x7 2006-06-30 65150 4921 1
x8 2006-07-10 65150 4921 1
And finally, I run this sql query:
SELECT clientid, (((a+ b + c) / 3) / 216647 * 10) AS Formula1
From FormTest
But then I got these results:
clientid Formula1
x1 0
x2 0
x3 0
x4 0
x4 0
x5 0
x6 0
x7 0
x8 0
Can anybody tell me what am I doing wrong?
Upvotes: 4
Views: 11682
Reputation: 31
Dividing integers will result in an integer (The remainder part will be ignored). Hence, when dividing, work with decimals or floats. This should work in addition to the float solutions given earlier. Replace (12,2) with your preferred precision:
SELECT clientid, (((
Cast(a as decimal(12,2)) +
Cast(b as decimal(12,2)) +
Cast(c as decimal(12,2))
) / 3) / 216647 * 10) AS Formula1
FROM FormTest
Upvotes: 0
Reputation: 12271
declare @a int
declare @b int
declare @c int
set @a=65150
set @b=4921
set @c=1
select convert(float,((@a+@b+@c)/ 216647.0 * 10) )
Upvotes: 0
Reputation: 11396
It's because you are doing integer division. You should convert one of the operands to float, or decimal (depending on the precision and purpose of the calculation you are doing), using something like:
((CAST((a+ b + c) AS FLOAT) / 3) / 216647 * 10)
or possibly:
(((a+ b + c) / 3.0) / 216647.0 * 10)
Upvotes: 5
Reputation: 5567
You're performing integer arithmetic, so your results will always be rounded down to the nearest whole number. Since you're dividing by 3, then by 216647, based on the numeric inputs your result is getting rounded down to 0 every time. You'll need to use either a decimal (exact) or floating point (approximate) data type and/or casting if you want to get non-integer results.
Upvotes: 2