CODEWITHSUNDEEP
ruby-on-railsruby
Srini K
Srini K

Reputation: 3365

Optimum way of writing this ruby code in one line

What is a good way of writing something like this in one line. The goal is to log the message at info level if the value is nil else in debug mode, along with proper message like the one shown. Seems simple, but writing 5 lines of code for something small like this keeps bothering me. I can wrap this in method, but would like to avoid if I can. Thanks.

if value.nil?
  Rails.logger.info "value: nil"
else
  Rails.logger.debug "value: #{value.inspect}"
end

Upvotes: 3

Views: 223

Answers (4)

Jörg W Mittag
Jörg W Mittag

Reputation: 369438

If you want it in one line, just remove the line breaks:

if value.nil? then Rails.logger.info "value: nil" else Rails.logger.debug "value: #{value.inspect}" end

But why, oh why, would anyone want to do this?

Upvotes: 0

Karthik Kumar Viswanathan
Karthik Kumar Viswanathan

Reputation: 1806

value.nil? ? Rails.logger.info "value: nil" : Rails.logger.debug "value: #{value.inspect}"

Upvotes: 0

odiszapc
odiszapc

Reputation: 4109

value.nil? ? (Rails.logger.info "value: nil") : (Rails.logger.debug "value: #{value.inspect}")

Another way you can try (this is not the same, but similar):

Rails.logger.send (value.nil? ? :info : :debug), "value: #{value.inspect}"

But the best way I think is to write you own logger, that automatically decides which variable in which flow is written:

NullLogger.log value

Upvotes: 8

VadimAlekseev
VadimAlekseev

Reputation: 2248

value ? Rails.logger.debug("value: #{value.inspect}") : Rails.logger.info("value: nil")

Upvotes: 0

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