Reputation: 862
I am trying to implement a high performance thread-safe caching. Here is the code I have implemented. I don't want any on demand computing. Can I use cache.asMap() and retrieve the value safely? Even if the cache is set to have softValues?
import java.io.IOException;
import java.util.concurrent.ConcurrentMap;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;
import com.google.common.cache.Cache;
import com.google.common.cache.CacheBuilder;
public class MemoryCache {
private static MemoryCache instance;
private Cache<String, Object> cache;
private MemoryCache(int concurrencyLevel, int expiration, int size) throws IOException {
cache = CacheBuilder.newBuilder().concurrencyLevel(concurrencyLevel).maximumSize(size).softValues()
.expireAfterWrite(expiration, TimeUnit.SECONDS).build();
}
static public synchronized MemoryCache getInstance() throws IOException {
if (instance == null) {
instance = new MemoryCache(10000, 3600,1000000);
}
return instance;
}
public Object get(String key) {
ConcurrentMap<String,Object> map =cache.asMap();
return map.get(key);
}
public void put(String key, Object obj) {
cache.put(key, obj);
}
}
Upvotes: 21
Views: 36307
Reputation: 11715
If you want high performance, why don't you instanciate the Cache statically instead of using a synchronized getInstance()?
Upvotes: 8
Reputation: 198211
Guava contributor here:
Yes, that looks just fine, although I'm not sure what the point is of wrapping the cache in another object. (Also, Cache.getIfPresent(key)
is fully equivalent to Cache.asMap().get(key)
.)
Upvotes: 32