Reputation: 3793
I am using Python 2.7. I have an alphanumeric string, on which I want to perform a encryption/decryption. Whatever I do should remain 2-way and the result should be alphanumeric too.
For example:
str = 'ma6546fbd'
encrypted_data = encrypt_function(str)
decrypted_data = decrypt_function(encrypted_data)
print decrypted_data # I get 'ma6546fbd'
What have I done:
I have written a function
def xor_crypt_string(data, key):
return ''.join(chr(ord(x) ^ ord(y)) for (x,y) in izip(data, cycle(key)))
This takes the data and a key and returns the result, the problem is that it includes special characters too, which I want to avoid.
Upvotes: 17
Views: 15114
Reputation: 11
Use PyCryptodome which is a fork of PyCrypto.
pip install pycryptodome
>>> from Crypto.Cipher import AES
>>> from Crypto import Random
>>> key = b'Sixteen byte key'
>>> iv = Random.new().read(AES.block_size)
>>> cipher = AES.new(key, AES.MODE_CFB, iv)
>>> msg = iv + cipher.encrypt(b'Attack at dawn')
>>> msg.hex()
'747a6a3c7357711773f4df5c3e8989dd055da5870d0bf7a967a5cd59ca98'
For decrytion:
>>> encrypted_data = '747a6a3c7357711773f4df5c3e8989dd055da5870d0bf7a967a5cd59ca98'
>>> cipher = AES.new(key, AES.MODE_CFB, iv)
>>> cipher.decrypt(binascii.unhexlify(encrypted_data))[len(iv):]
Note that:
A cipher object is stateful: once you have decrypted a message you cannot decrypt (or encrypt) another message with the same object.
Upvotes: 1
Reputation: 87124
How strict is the alphanumeric requirement?
How about base64 encoding the result of your existing encryption function? You might end up with a few stray '=' padding characters, but you could trim these and calculate and handle the extra padding.
def xor_crypt_string(plaintext, key):
ciphertext = ''.join(chr(ord(x) ^ ord(y)) for (x,y) in izip(plaintext, cycle(key)))
return ciphertext.encode('base64')
def xor_decrypt_string(ciphertext, key):
ciphertext = ciphertext.decode('base64')
return ''.join(chr(ord(x) ^ ord(y)) for (x,y) in izip(ciphertext, cycle(key)))
Upvotes: 2
Reputation: 54107
If you want serious encryption (read unbreakable) then I'd use AES from pycrypto something like this.
>>> from Crypto.Cipher import AES
>>> from Crypto import Random
>>> key = b'Sixteen byte key'
>>> iv = Random.new().read(AES.block_size)
>>> cipher = AES.new(key, AES.MODE_CFB, iv)
>>> msg = iv + cipher.encrypt(b'Attack at dawn')
>>> msg.encode("hex")
'e10e096aabff9db382abe8d704404995a7b64d72a4e1b9e5208912d206c4'
That is your ascii message. Now decode the message like this
>>> recv='e10e096aabff9db382abe8d704404995a7b64d72a4e1b9e5208912d206c4'
>>> cipher.decrypt(recv.decode("hex"))[len(iv):]
'Attack at dawn'
>>>
Any encryption method you make up yourself will be easily breakable by an expert and the one you've shown above falls into that category.
Upvotes: 42