Reputation: 229
I want to delete a number of jobs from a q. The command to delete the job is qdel JOBid
.
Initially, I tried to use the subprocess module, but I got an error: #!/usr/bin/env python
import sys, os, subprocess as sp
lo = sys.argv[1]
hi = sys.argv[2]
lo = int(lo)
hi = int(hi)
for i in range(lo,hi):
print "i is %d"%i
p=sp.Popen(['qdel %d'%i],stdout=sp.PIPE)
#os.system('qdel %d'%i)
So this did not work. The error I got was
Traceback (most recent call last):
File "del.py", line 14, in <module>
p=sp.Popen(['qdel %d'%i],stdout=sp.PIPE)
File "/usr/lib64/python2.6/subprocess.py", line 639, in __init__
errread, errwrite)
File "/usr/lib64/python2.6/subprocess.py", line 1228, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Then I commented out the subprocess line and used os and it worked immediately. I think I don't fully understand the subprocess module
#!/usr/bin/env python
import sys, os, subprocess as sp
lo = sys.argv[1]
hi = sys.argv[2]
lo = int(lo)
hi = int(hi)
for i in range(lo,hi):
print "i is %d"%i
#p=sp.Popen(['qdel %d'%i],stdout=sp.PIPE)
os.system('qdel %d'%i)
The above code worked flawlessly. I just want to know why and what the advantages are of the subprocess module. Also, I am using a unix shell
Upvotes: 12
Views: 6840
Reputation: 100
I was also getting same issue. Using shell=True as one of the parameter solved my problem.
Upvotes: 0
Reputation: 5154
If you read manual, you can see that your call to Popen
is wrong: you should pass not a single command, but an array of arguments:
p=sp.Popen(['qdel', '%d'%i],stdout=sp.PIPE)
Alternatively, as sc0tt's answer points out, you can use shell=True
, but this has some disadvantages in more complex cases: you would have to manually escape all the variable data in the command in case it contains, for example, filenames with spaces or anything much more potentially harmful (like ;
)
Upvotes: 3
Reputation: 1348
You want to use shell=True on your Popen call.
p=sp.Popen(['qdel %d'%i], shell=True, stdout=sp.PIPE)
Upvotes: 3