Reputation: 189
I am looking to generate a number sequence where each number is between 70 and 100 there will be x numbers in the sequence and it will give and average of y. What would this algorithm look like?
Upvotes: 5
Views: 2812
Reputation: 262534
I think it is impossible for them to be uniformly distributed between 70 and 100 and have a given average at the same time.
What you can do is generate random numbers that have a given average and then scale them to fit into [70, 100] (but they will not be uniformly distributed there).
generate random numbers [0..1(
calculate their average
multiply all of them to match the required average
if any of them does not fit into [70, 100], scale all of them again by reducing their distance from y
by the same factor (this does not change the average). x[i] = y + (x[i] - y)*scale
You will end up with numbers that are all in the range [70, 100(, but they will be uniformly distributed across a different (but overlapping) interval that is centered on y. Also, this approach only works with real/floating-point numbers. If you want integers, you got a combinational problem on your hands.
Upvotes: 2
Reputation: 2095
Random r = new Random();
List<int> l = new List<int>();
Console.Write("Please enter amount of randoms ");
int num = (int)Console.Read();
for (int i = 0; i < num; i++)
{
l.Add(r.Next(0, 30) + 70);
}
//calculate avg
int sum = 0;
foreach (int i in l)
{
sum += i;
}
Console.Write("The average of " + num + " random numbers is " + (sum / num));
//to stop the program from closing automatically
Console.ReadKey();
Upvotes: 0
Reputation: 2071
Python example
import random
import time
x = 10
total = 0
avg = 0
random.seed(time.time())
for x in range(10):
total += random.randint(70,100)
avg = total /x
print "total: ", total
print "avg: ", avg
Upvotes: 0