Reputation: 21934
I don't know if this is a simple question or impossible or anything, but I couldn't find anything on it so I figured I would ask it.
Is it possible to return values from a while loop while that loop is still running? Basically what I want to do is have a vector constantly updating within a while loop, but able to return values when asked without stopping the while loop. Is this possible? Do I just have to break up the program and put the while loop in a separate thread, or can I do it within one function?
Also I would prefer a method that is not computationally intensive (obviously), and one compatible with a rate-limited while loop as this one will certainly be rate-limited.
Again, if this is a stupid question just tell me and I will delete it, but I wasn't able to find documentation on this.
Code I am trying to implement this with:
def update(self, x_motion, y_motion, z_motion):
self.x_pos += self.x_veloc
self.y_pos += self.y_veloc
self.z_pos += self.z_veloc
self.x_veloc += self.x_accel
self.y_veloc += self.y_accel
self.z_veloc += self.z_accel
self.x_accel = x_motion[2]
self.y_accel = y_motion[2]
self.z_accel = z_motion[2]
while True:
self.update(x_motion, y_motion, z_motion)
print vector.x_accel
Something along those lines at least. It is important that these return outside of the while loop, so that the while loop runs in the background, but it only gives results when asked, or something like that.
Upvotes: 3
Views: 11515
Reputation: 5759
What you are looking for is yield
:
def func():
while True:
yield "hello"
for x in func():
print(x)
Generators can also be written like list comprehensions:
Have a look at this question:
What does the "yield" keyword do?
Upvotes: 4
Reputation: 546
If I understand you and the code you want to do.
I may think of trying to find equations of position, velocity and acceleration with respect to time.
So you won't need to keep, the while loop running, what you need is to convert it to a function, and using the time difference between the 2 function calls, you can perform the calculations you want, only when you call the function, rather than having the while loop running all the time.
Upvotes: 0
Reputation: 799310
Create a generator instead.
def triangle():
res = 0
inc = 1
while True:
res += inc
inc += 1
yield res
t = triangle()
print next(t)
print next(t)
print next(t)
print next(t)
EDIT:
Or perhaps a coroutine.
def summer():
res = 0
inc = 0
while True:
res += inc
inc = (yield res)
s = summer()
print s.send(None)
print s.send(3)
print s.send(5)
print s.send(2)
print s.send(4)
Upvotes: 6