CODEWITHSUNDEEP
phpmysql
La Myse
La Myse

Reputation: 47

foreach invalid argument supplied and mysql fetch array issue

i have this code which i use to print some fields from the database.

My problem is that i get this error about foreach invalid argument supplied and a mysql fetch array problem.

The code is this:

foreach( $checked1 as $key => $value){
    echo "<th> $value </th>";
}
echo "</tr></thead>";

while($row = mysql_fetch_array($result)){

Where $checked1 is an array

$checked1 = $_POST['checkbox'];

What's the problem here?

The whole code:

    <?php

echo "<div id='table-3'>"; 
    if(isset($_POST['Submit'])) {
    echo "<pre>";
    $checked1 = $_POST['checkbox'];
    $checked = implode(',', $_POST['checkbox']);

    }
    $con = mysql_connect('localhost','user','passwd');
    mysql_query("SET NAMES UTF8");

    if (!$con)
    {
    die('Could not connect: ' . mysql_error());
    }

    mysql_select_db("db_name", $con);

    $result = mysql_query("SELECT $checked FROM hostess");
    echo "<table >";
    echo "<thead><tr>";
    if(is_array($_POST['checkbox'])){
 foreach( $checked1 as $key => $value){
    echo "<th> $value </th>";
    }
    echo "</tr></thead>";

    } else {
echo "Checkbox is not an array.";
}



   while($row = mysql_fetch_array($result)){
echo "<tr>";
foreach($checked1 as $key => $value){
if($value == 'photo'){
 echo "<td> <img src=foto/photo1/".$row[$value] . "></td>";

}   else if($value == 'photo2'){
echo "<td><img src=foto/photo2/".$row[$value] . "></td></td>";

}
else if( $value == 'photo2' && $value == 'photo'){
    echo "<td> <img src=foto/photo1/".$row[$value] . "></td>";
    echo "<td><img src=foto/photo2/".$row[$value] . "></td></td>";
}
else{

    echo "<td>" . $row[$value] . "</td>";
}
}echo "</tr>";
    }
    echo "</table>";

Upvotes: 0

Views: 294

Answers (2)

bgallz
bgallz

Reputation: 111

What is your $_POST['checkbox'] called in your HTML form? It should be something like:

<input type="checkbox" name="checkbox[]" value="1" />

Check to make sure your checkbox values are coming through as arrays. Do the following:

if(is_array($_POST['checkbox'])){
// contiue with foreach...
} else {
echo "Checkbox is not an array.";
}

Upvotes: 1

dev-null-dweller
dev-null-dweller

Reputation: 29462

Either $_POST['checkbox'] is not defined (no checkbox checked while sending form) or is not an array (input name does not contain [] in the end);

You should always check if variable contain what you want before performing any operation on it, ex:

if(is_array($checked1)){
    foreach( ... ){  
    }
}

$result = mysql_query(' ... ');

if(!$result){
   die(mysql_error());
}

Upvotes: 1

Related Questions