Reputation: 583
I'm trying to upload two different files into two different database fields on same form.
------------------------------------
reportid | name | image | template |
------------------------------------
this is the table look. So I want to upload files to image and template. My model:
public class Report
{
[Key]
public int ReportID { get; set; }
[Required]
public string Name { get; set; }
public byte[] Image { get; set; }
public byte[] Template { get; set; }
}
My Create method in controller:
public ActionResult Create(Report report, HttpPostedFileBase file, HttpPostedFileBase temp)
{
if (ModelState.IsValid)
{
if (file != null && file.ContentLength > 0)
{
using (MemoryStream ms = new MemoryStream())
{
file.InputStream.CopyTo(ms);
report.Image = ms.GetBuffer();
}
}
if (temp != null && temp.ContentLength > 0)
{
using (MemoryStream ms1 = new MemoryStream())
{
temp.InputStream.CopyTo(ms1);
report.Template = ms1.GetBuffer();
}
}
db.Reports.Add(report);
db.SaveChanges();
db.Configuration.ValidateOnSaveEnabled = true;
return RedirectToAction("Index");
}
And part of view concerning uploads:
<div class="editor-label">
<%:Html.LabelFor(model => model.Image) %>
</div>
<div class="editor-field">
<input type="file" id="fuImage" name="file" />
</div>
<div class="editor-label">
<%:Html.Label("Template") %>
</div>
<div class="editor-field">
<input type="file" id="temp" name="temp"/>
</div>
<p>
<input type="submit" value="Create" />
</p>
I'm quite stuck in this since I can not use IEnumerable<HttpPostedFileBase> files
as a parameter in Create
method because I need to save it in a different field, or can I? How should I approach this? Please help :S
Note: Image upload works fine.
Upvotes: 2
Views: 2140
Reputation: 218752
Why not use IEnumerable<HttpPostedFileBase>
? You may use it like this.
[HttpPost]
public ActionResult Create(Report report, IEnumerable<HttpPostedFileBase> files)
{
if (ModelState.IsValid)
{
//Let's take first file
if(files.ElementAt(0)!=null)
{
var file1=files.ElementAt(0);
if (file1!= null && file1.ContentLength > 0)
{
//do processing of first file
}
}
//Let's take the second one now.
if(files.ElementAt(1)!=null)
{
var temp =files.ElementAt(1);
if (temp!= null && temp.ContentLength > 0)
{
//do processing of second file here
}
}
}
//Do your code for saving the data.
return RedirectToAction("Index");
}
EDIT : After seeing your View Markup in your EDIT.
The name of the file input element should be same as the parameter name in your action method. (files
in this example)
@using (Html.BeginForm("Create", "Home", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<b>File 1</b>
<input type="file" name="files" id="file1" />
<b>File 2</b>
<input type="file" name="files" id="file2" />
<input type="submit" />
}
This code assumes that read ONLY the first 2 entries from the collection.Since you wanted only 2 files, i hardcoded the indexes.
Phil has a nice blog post explaining about it very nicely.
Upvotes: 6