Reputation:
I have the following:
int count = args.length;
Strange as it might seem I want to find out the array length without using the length field. Is there any other way?
Here's what I already (without success) tried:
int count=0; while (args [count] !=null) count ++;
int count=0; while (!(args[count].equals(""))) count ++;}
Upvotes: 3
Views: 22950
Reputation: 1
int[] intArray = { 2, 4, 6, 8, 7, 5, 3 };
int count = 0;
// System.out.println("No of Elements in an Array using Length:
// "+intArray.length);
System.out.println("Elements in an Array: ");
for (int i : intArray) {
System.out.print(i + " ");
count++;
}
System.out.println("\nCount: " + count);
Upvotes: 0
Reputation: 11
public class ArrayLength {
static int number[] = { 1, 5, 8, 5, 6, 2, 4, 5, 1, 8, 9, 6, 4, 7, 4, 7, 5, 1, 3, 55, 74, 47, 98, 282, 584, 258, 548,
56 };
public static void main(String[] args) {
calculatingLength();
System.out.println(number.length);
}
public static void calculatingLength() {
int i = 0;
for (int num : number) {
i++;
}
System.out.println("Total Size Of Array :" + i);
}
}
Upvotes: 0
Reputation: 23349
I don't think that there is any need to do this. However, the easiest way to do this ,is to use the enhanced for loop
int count=0;
for(int i:array)
{
count++;
}
System.out.println(count);
Upvotes: 5
Reputation: 1367
You cannot use [] to access an array if the index is out of bound.
You can use for-each loop
for (String s: args){
count++;
}
Upvotes: 0
Reputation: 1863
I'm not sure why you would want to do anything else, but this is just something I came up with to see what would work. This works for me:
int count = 0;
int[] someArray = new int[5];
int temp;
try
{
while(true)
{
temp = someArray[count];
count++;
}
}
catch(Exception ex)
{
System.out.println(count);
}
Upvotes: 3