Reputation: 33605
my jsps are under WEB-INF/jsp/ , and following is my web.xml:
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Checkout</display-name>
<servlet>
<servlet-name>myservlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>myservlet</servlet-name>
<url-pattern>*.action</url-pattern>
</servlet-mapping>
</web-app>
and here's mapping of page product.jsp which i am trying to access:
@Controller
@RequestMapping("/product.action")
public class ProductController {
/**
* Show the product selection form
*
* @return
*/
@RequestMapping(method=RequestMethod.GET)
public String get() {
return "products.jsp";
}
}
when trying to access the page from the following link:
http://localhost:8080/myapp/product.action
i am getting 404
in the browser, and i get the following warning in the console:
Jun 28, 2012 10:55:23 AM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/myapp/product.action] in DispatcherServlet with name 'myservlet'
am i missing something in the configuration ? please advise, thanks.
EDIT: i tried adding the viewResolver bean to applicationContext with no luck:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<context:component-scan base-package="com.myapp"/>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>
</beans>
Upvotes: 3
Views: 40826
Reputation: 1
Solution for this error: org.springframework.web.servlet.DispatcherServlet noHandlerFound (No mapping found)
Simply follow these steps:
Right click on the project > Build Path > Configure Build path > Deployment Assembly > Add(right hand side) > Folder > Add your views folder > Apply and Close
Upvotes: 0
Reputation: 139
Change this <url-pattern>*.action</url-pattern>
to <url-pattern>/*.action</url-pattern>
Check base-package name in .xml file when you learn from others tutorial
Hope it should work fine
Upvotes: 0
Reputation: 1
Check the package name spring-servlet.xml , if it is correctly spelled or not. That might be the issue. I faced while starting the Spring MVC
Upvotes: -1
Reputation: 1546
Follow the rule whatever Sunil has mentioned. I see one issue in your spring configuration xml that you don't have the
<mvc:annotation-driven />
You need this to register the Controller
along with
<context:component-scan base-package="com.myapp"/>
Upvotes: 3
Reputation: 1
İf you use viewResolver in context xml , you should change get method return statemant to "products" and be sure the folder hierarchy is right
Upvotes: 0
Reputation: 441
Use this class="org.springframework.web.servlet.view.UrlBasedViewResolver" instead of class="org.springframework.web.servlet.view.InternalResourceViewResolver"
in your application context bean.
Upvotes: 0
Reputation: 33605
problem was that the controller wasn't detected.
i changed the base-package from com.myapp
to com.myapp.controller
, and it works fine now.
Upvotes: 1
Reputation: 3004
When you specify the RequestMapping, URI should not have extension. Dispatcher servlet will omit it from the request URI while searching for URI mapping.
Use @RequestMapping("/product")
it should work.
Second thing when you are using view resolver just return the name of the JSP file. Do not append .jsp extension, InternalViewResolver will do it for you.
Upvotes: 2