CODEWITHSUNDEEP
phpif-statement
David Morin
David Morin

Reputation: 485

Only show link if conditional equals true

I want the link to appear only when $data['block'] equals to 1, 3 or 4. Not if it equals to 2 or 5.

<td style="font-size:18px;color:#f0cb01;">
    <a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>
</td>

EDIT

while ($data = mysql_fetch_array($query)) {

echo '
<tr style="background-color:#576c11;">
    <td style="font-size:18px; color:#f0cb01;">'.$data["keyword"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["block"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["phone"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["Reason"].'</td>
    <td style="font-size:18px;color:#f0cb01;"><a href="kickcodes.php?id='.$data  ["block"].'">Kickcodes</a></td>'

    echo '<td style="font-size:18px;color:#f0cb01;">'; 
if( $data['block'] == 1 || $data['block'] == 3 || $data['block'] == 4)  
{ 
echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>'; 
} else  
{ 
echo '<span>Reason Codes</span>'; // Or echo nothing 
} 
echo '</td>';

Upvotes: 1

Views: 1969

Answers (3)

Sabari
Sabari

Reputation: 6335

 echo '<td style="font-size:18px;color:#f0cb01;">';
 if ($data['block'] == 1 || $data['block'] == 3 || $data['block'] == 4) {
    echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>';
 }
 echo '</td>';

if you are using words instead of numbers you can do like :

echo '<td style="font-size:18px;color:#f0cb01;">';

if ($data['block'] == 'block 1' || $data['block'] == 'block 3' || $data['block'] == 'block 4') {
  echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>';
}
echo '</td>';

Hope this helps :)

Upvotes: 1

nickb
nickb

Reputation: 59699

Just put the conditions you want the link to occur within an if statement:

echo '<td style="font-size:18px;color:#f0cb01;">';
if( $data['block'] == 1 || $data['block'] == 3 || $data['block'] == 4) 
{
    echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>';
} else 
{
    echo '<span>Reason Codes</span>'; // Or echo nothing
}
echo '</td>';

It wouldn't make sense in a table to omit a <td> tag, which is why I placed it outside of the if statement.

while ($data = mysql_fetch_array($query)) {

echo '
<tr style="background-color:#576c11;">
    <td style="font-size:18px; color:#f0cb01;">'.$data["keyword"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["block"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["phone"].'</td>
    <td style="font-size:18px;color:#f0cb01;">'.$data["Reason"].'</td>
    <td style="font-size:18px;color:#f0cb01;"><a href="kickcodes.php?id='.$data  ["block"].'">Kickcodes</a></td>';

    echo '<td style="font-size:18px;color:#f0cb01;">'; 
    if( $data['block'] == 1 || $data['block'] == 3 || $data['block'] == 4)  
    { 
        echo '<a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>';     
    } 
    else  
    { 
       echo '<span>Reason Codes</span>'; // Or echo nothing 
    } 
    echo '</td>';

Upvotes: 1

sushil
sushil

Reputation: 2671

This will work:

<td style="font-size:18px;color:#f0cb01;">
 <?php if (in_array($data["block"], array(1,3,4)){?>
    <a href="kickcodes.php?id='.$data["block"].'">Reason Codes</a>
<?php}?>
</td>

Upvotes: 3

Related Questions