Reputation: 2337
I have a method that gets a string and change that to a particular date format but the thing is the date will be any format For Example
16 July 2012
March 20 2012
2012 March 20
So I need to detect the string is in which file format.
I use the below code to test it but I get exception if the file format changes.
private String getUpdatedDate(String updated) {
Date date;
String formatedDate = null;
try {
date = new SimpleDateFormat("d MMMM yyyy", Locale.ENGLISH)
.parse(updated);
formatedDate = getDateFormat().format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return formatedDate;
}
Upvotes: 11
Views: 31053
Reputation: 31
My library FTA (https://github.com/tsegall/fta) is designed to solve exactly this problem (among others). Here is an example:
import java.util.Locale;
import com.cobber.fta.dates.DateTimeParser;
import com.cobber.fta.dates.DateTimeParser.DateResolutionMode;
public abstract class DetermineDateFormat {
public static void main(final String[] args) {
final DateTimeParser dtp = new DateTimeParser(DateResolutionMode.MonthFirst, Locale.ENGLISH);
System.err.println(dtp.determineFormatString("26 July 2012"));
System.err.println(dtp.determineFormatString("March 9 2012"));
// Note: Detected as MM/dd/yyyy despite being ambiguous as we indicated MonthFirst above when insufficient data
System.err.println(dtp.determineFormatString("07/04/2012"));
System.err.println(dtp.determineFormatString("2012 March 20"));
System.err.println(dtp.determineFormatString("2012/04/09 18:24:12"));
}
Which will give the following output:
MMMM d yyyy
MM/dd/yyyy
yyyy MMMM dd
yyyy/MM/dd HH:mm:ss
Upvotes: 2
Reputation: 364
I encountered this issue as well, where at some places:
Hopefully, #2 will help you in atleast few cases.
Upvotes: 0
Reputation: 5837
BalusC wrote a simple DateUtil
which serves for many cases. You may need to extend this to satisfy your requirements.
Here is the link: https://balusc.omnifaces.org/2007/09/dateutil.html
and the method you need to look for determineDateFormat()
Upvotes: 5
Reputation: 151
public static String detectDateFormat(Context context, String inputDate, String requiredFormat) {
String tempDate = inputDate.replace("/", "").replace("-", "").replace(" ", "");
String dateFormat = "";
if (tempDate.matches("([0-12]{2})([0-31]{2})([0-9]{4})")) {
dateFormat = "MMddyyyy";
} else if (tempDate.matches("([0-31]{2})([0-12]{2})([0-9]{4})")) {
dateFormat = "ddMMyyyy";
} else if (tempDate.matches("([0-9]{4})([0-12]{2})([0-31]{2})")) {
dateFormat = "yyyyMMdd";
} else if (tempDate.matches("([0-9]{4})([0-31]{2})([0-12]{2})")) {
dateFormat = "yyyyddMM";
} else if (tempDate.matches("([0-31]{2})([a-z]{3})([0-9]{4})")) {
dateFormat = "ddMMMyyyy";
} else if (tempDate.matches("([a-z]{3})([0-31]{2})([0-9]{4})")) {
dateFormat = "MMMddyyyy";
} else if (tempDate.matches("([0-9]{4})([a-z]{3})([0-31]{2})")) {
dateFormat = "yyyyMMMdd";
} else if (tempDate.matches("([0-9]{4})([0-31]{2})([a-z]{3})")) {
dateFormat = "yyyyddMMM";
} else {
}
try {
String formattedDate = new SimpleDateFormat(requiredFormat, Locale.ENGLISH).format(new SimpleDateFormat(dateFormat).parse(tempDate));
Toast.makeText(context, formattedDate, Toast.LENGTH_SHORT).show();
return formattedDate;
} catch (Exception e) {
Toast.makeText(context, "Please check the date format", Toast.LENGTH_SHORT).show();
return "";
}
}
Upvotes: 0
Reputation: 11
Use the regex to parse the string for date. This regex can detect any kind of date format. The sample code here is not including time yet. You can change the code to add more parts of the date like time and time zone...The month name is depending on default language locale of the system.
import java.io.IOException;
import java.text.DateFormatSymbols;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.HashMap;
import java.util.Iterator;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class DateUtils {
static String MONTH="";
static String dateRegEx="";
static Pattern DatePattern;
static HashMap<String, Integer> monthMap = new HashMap<String, Integer>();
static {
initializeMonthName();
dateRegEx="(?i)(\\d{1,4}|"+MONTH+")[-|/|.|\\s+]?(\\d{1,2}|"+MONTH+")[-|/|.|,]?[\\s+]?(\\d{1,4}|"+MONTH+")[\\s+|\\t|T]?(\\d{0,2}):?(\\d{0,2}):?(\\d{0,2})[.|,]?[\\s]?(\\d{0,3})?([+|-])?(\\d{0,2})[:]?(\\d{0,2})[\\s+]?([A|P]M)?";
DatePattern = Pattern.compile(dateRegEx);
}
private static void initializeMonthName() {
String[] monthName=getMonthString(true);
for(int i=0;i<12;i++){
monthMap.put(monthName[i].toLowerCase(), Integer.valueOf(i+1));
}
monthName=getMonthString(false);
for(int i=0;i<12;i++){
monthMap.put(monthName[i].toLowerCase(), Integer.valueOf(i+1));
}
Iterator<String> it = monthMap.keySet().iterator();
while(it.hasNext()){
String month=it.next();
if(MONTH.isEmpty()){
MONTH=month;
}else{
MONTH=MONTH + "|" + month;
}
}
}
public static boolean isInteger(Object object) {
if(object instanceof Integer) {
return true;
} else {
try{
Integer.parseInt(object.toString());
}catch(Exception e) {
return false;
}
}
return true;
}
public static String[] getMonthString(boolean isShort) {
DateFormatSymbols dfs = new DateFormatSymbols();
if (isShort) {
return dfs.getShortMonths();
} else {
return dfs.getMonths();
}
}
public static int getMonthMap(String value) {
if(monthMap.get(value)==null){
return 0;
}
return monthMap.get(value).intValue();
}
public static long parseDate(String value){
Matcher matcher = DatePattern.matcher(value);
int Year=0, Month=0, Day=0;
boolean isYearFound=false;
boolean isMonthFound=false;
boolean isDayFound=false;
if(matcher.find()) {
for(int i=1;i<matcher.groupCount();i++){
String data=matcher.group(i)==null?"":matcher.group(i);
if(data.equalsIgnoreCase("null")){
data="";
}
//System.out.println(String.valueOf(i) + ": " + data);
switch(i){
case 1:
if(!data.isEmpty()){
if(isInteger(data)){
Integer YMD = Integer.valueOf(data);
if(YMD==0){
return 0;
}
if(YMD>31){
Year = YMD.intValue();
isYearFound = true;
}else if(YMD>12){
Day = YMD.intValue();
isDayFound = true;
}else {
Month=YMD.intValue();
isMonthFound=true;
}
}else {
Month = getMonthMap(data.toLowerCase());
if(Month==0){
return 0;
}
isMonthFound=true;
}
}else {
return 0;
}
break;
case 2:
if(!data.isEmpty()){
if(isInteger(data)){
Integer YMD = Integer.valueOf(data);
if(YMD==0){
return 0;
}
if(YMD>31){
if(isYearFound) {
return 0;
}
Year = YMD.intValue();
isYearFound = true;
}else if(YMD>12){
if(isDayFound) {
return 0;
}
Day = YMD.intValue();
isDayFound = true;
}else {
if(isMonthFound){
Day=YMD.intValue();
isDayFound=true;
}else{
Month=YMD.intValue();
isMonthFound=true;
}
}
}else {
if(isMonthFound){
Day=Month;
isDayFound=true;
}
Month = getMonthMap(data.toLowerCase());
if(Month==0){
return 0;
}
isMonthFound=true;
}
}else {
return 0;
}
break;
case 3:
if(!data.isEmpty()){
if(isInteger(data)){
Integer YMD = Integer.valueOf(data);
if(YMD==0){
return 0;
}
if(YMD>31){
if(isYearFound) {
return 0;
}
Year = YMD.intValue();
isYearFound = true;
}else if(YMD>12){
if(isDayFound) {
return 0;
}
Day = YMD.intValue();
isDayFound = true;
}else {
if(isMonthFound){
Day=YMD.intValue();
isDayFound=true;
}else {
Month = YMD.intValue();
isMonthFound=true;
}
}
}else {
if(isMonthFound){
Day=Month;
isDayFound=true;
}
Month = getMonthMap(data.toLowerCase());
if(Month==0){
return 0;
}
isMonthFound=true;
}
}else {
return 0;
}
break;
case 4:
//hour
break;
case 5:
//minutes
break;
case 6:
//second
break;
case 7:
//millisecond
break;
case 8:
//time zone +/-
break;
case 9:
//time zone hour
break;
case 10:
// time zone minute
break;
case 11:
//AM/PM
break;
}
}
}
Calendar c = Calendar.getInstance();
c.set(Year, Month-1, Day, 0, 0);
return c.getTime().getTime();
}
public static void main(String[] argv) throws IOException {
long d= DateUtils.parseDate("16 July 2012");
Date dt = new Date(d);
SimpleDateFormat df2 = new SimpleDateFormat("d MMMM yyyy");
String dateText = df2.format(dt);
System.out.println(dateText);
d= DateUtils.parseDate("March 20 2012");
dt = new Date(d);
dateText = df2.format(dt);
System.out.println(dateText);
d= DateUtils.parseDate("2012 March 20");
dt = new Date(d);
dateText = df2.format(dt);
System.out.println(dateText);
}
}
Upvotes: 0
Reputation: 1076
Apache commons has a utility method to solve this problem . The org.apache.commons.lang.time.DateUtils class has a method parseDateStrictly
public static Date parseDateStrictly(String str,
String[] parsePatterns)
throws ParseException
Parameters:
str - the date to parse, not null
parsePatterns - the date format patterns to use, see SimpleDateFormat, not null
Parses a string representing a date by trying a variety of different parsers.
The parse will try each parse pattern in turn. A parse is only deemed successful if it parses the whole of the input string. If no parse patterns match, a ParseException is thrown.
The parser parses strictly - it does not allow for dates such as "February 942, 1996".
Upvotes: 2
Reputation: 1145
If you're using Joda Time (awesome library btw) you can do this quite easily:
DateTimeParser[] dateParsers = {
DateTimeFormat.forPattern("yyyy-MM-dd HH").getParser(),
DateTimeFormat.forPattern("yyyy-MM-dd").getParser() };
DateTimeFormatter formatter = new DateTimeFormatterBuilder().append(null, dateParsers).toFormatter();
DateTime date1 = formatter.parseDateTime("2012-07-03");
DateTime date2 = formatter.parseDateTime("2012-07-03 01");
Upvotes: 3
Reputation: 691943
Decide which formats are expected, and try to parse the date with each format, one after the other. Stop as soon as one of the formats parses the date without exception.
Upvotes: 0
Reputation: 272337
Perhaps the easiest solution is to build a collection of date formats you can reasonably expect, and then try the input against each one in turn.
You may want to flag ambiguous inputs e.g. is 2012/5/6 the 5th June or 6th May ?
Upvotes: 9