CODEWITHSUNDEEP
bashfunction
Zombo
Zombo

Reputation: 1

Bash, call a function sourced from a script?

Say I have 2 scripts

test1.sh

#!/bin/sh
. ./test2.sh
foo

test2.sh

#!/bin/sh
foo(){
  echo "bar"
}

If I call first script it is ok

$ ./test1.sh
bar

But if I try to call foo after that it will not work.

$ foo
bash: foo: command not found

Upvotes: 4

Views: 5368

Answers (3)

mouviciel
mouviciel

Reputation: 67831

When you execute ./test1.sh, a subprocess is spawned. When test1.sh sources test2.sh, only the context of that subprocess is modified when foo() is defined. As soon as test1.sh completes, the subprocess terminates and your interactive shell has no knowledge of foo().

Upvotes: 10

Zombo
Zombo

Reputation: 1

If I source test1.sh it gives the desired result.

$ . test1.sh
bar

$ foo
bar

Upvotes: 0

Ivaylo Strandjev
Ivaylo Strandjev

Reputation: 70931

If you call source test2.sh you will get the result you want. If you want to be able to call foo whenever you start new terminal, place its definition in .bashrc or .profile file.

Upvotes: 3

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