CODEWITHSUNDEEP
c++parametersdefault-value
user272671
user272671

Reputation: 657

C++ Using default values for parameters

I am new to C++ (from C# background) and I have a function with the following signature 

 void AddBenchNode(ref_ptr<Group> root ,ref_ptr<Node> benches, bool setAttitude = false, float scale_x =.15, float scale_y =15, float scale_z = 15, int positionx = 250, int positiony = 100, int positionz =0 )
{

}

But when I try to call the code as below, I get an error which says function does not take 4 arguments. 

//then I try to call my function like so
AddBenchNode(root, benches, false, 250);

but I instead get the following error message

error C2660: 'AddBenchNode' : function does not take 3 arguments

Would appreciate an explanation of how C++ does this instead?

Upvotes: 1

Views: 918

Answers (1)

Wernsey
Wernsey

Reputation: 5491

Check the prototype in your .hpp file. It's probably declared as

void AddBenchNode(ref_ptr<Group> root ,ref_ptr<Node> benches, bool setAttitude, 
                  float scale_x, float scale_y, float scale_z, int positionx, 
                  int positiony, int positionz);

EDIT: The prototype in the header should be 

void AddBenchNode(ref_ptr<Group> root ,ref_ptr<Node> benches, bool setAttitude = false, float scale_x =.15, float scale_y =15, float scale_z = 15, int positionx = 250, int positiony = 100, int positionz =0 );

And your cpp file should then only have

void AddBenchNode(ref_ptr<Group> root ,ref_ptr<Node> benches, bool setAttitude, float scale_x, float scale_y, float scale_z, int positionx, int positiony, int positionz)
{

}

That is, the default parameters are in the prototype, not in the actual definition.

Upvotes: 7

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