CODEWITHSUNDEEP
java
Johan
Johan

Reputation: 35213

Java linq equivalent for getting property in list with highest value

Im having a list of results, ArrayList<PlacedObject> result:

for(PlacedObject po : result){

     float[] results = new float[3];

     Location.distanceBetween(lastlocation.getLatitude()
     ,lastlocation.getLongitude()
     ,Double.parseDouble(po.lat)
     ,Double.parseDouble(po.lng) ,
     results);

     po.distance = results[0];
}

After the po.distance is set, i would like to sort my list by the distance property. In c# i would use linq, but is there any similar solution in java?

Thanks

Current solution:

Collections.sort(result, new Comparator<PlacedObject>(){
public int  compare(PlacedObject s1, PlacedObject s2) {
    return (int) (s1.distance - s2.distance);
}
});

Upvotes: 0

Views: 194

Answers (1)

Konrad Reiche
Konrad Reiche

Reputation: 29543

This is accomplished with the implementation of a Comparator<T> class:

A comparison function, which imposes a total ordering on some collection of objects. Comparators can be passed to a sort method (such as Collections.sort or Arrays.sort) to allow precise control over the sort order.

It could be applied to your list with Collections.sort(list, comparator). Basically you implement your own Comparator and pass it to the method.

An implementation could for instance use an anonymous inner class:

Collections.sort(list, new Comparator<PlacedObject>() {

    @Override
    public int compare(PlacedObject po1, PlacedObject po2) {
        return Double.valueOf(po1.distance).compareTo(po2.distance);
    }
});

If you are only intersted in the maximum, as your headline indicates, there is also Collections.max which is applied in the identical way.

Upvotes: 3

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