CODEWITHSUNDEEP
pythonfiletext
user1393258
user1393258

Reputation:

Converting format of the text in a file by using python

I want to convert a head file which is written in C to a class in python

Basically, the format of the head file in C (a file called header.c is like following:

#define ATTR_A          (HELLO +1L)     /*FSDSDF*/
#define ATTR_B          (HELLO +2L)     /*FSFSSF*/

What I want to do is writing a simple script which can read the text from header.c and then convert the format to a python calss and stored the result to a file called header.py. After conversion, it will be:

ATTR_A        = (HELLO +1L)
ATTR_B        = (HELLO +2L)

I know how to read the file and how to store the converted result into header.py, but I know how to do the conversion. Can someone please help me? Thanks!

Upvotes: 0

Views: 134

Answers (2)

2342G456DI8
2342G456DI8

Reputation: 1809

I think the best way to do this is using re here.

>>> import re
>>> testinput = '#define ATTR_A          (HELLO +1L)     /*FSDSDF*/'
>>> r = re.split(r'#define (\w*)(\s*)(\(.*\))', testinput)
>>> print '%s = %s' %(r[1], r[3])
ATTR_A = (HELLO +1L)

(\w*) is used to extract the 'ATTR_A'

(\s*) is used to extract the whitespaces

Inside (\(.*\)), \( actually matches ( and \) mataches ). .* matches any character except a newline.

So, after the split, r= ['', 'ATTR_A', ' ', '(HELLO +1L)', ' /*FSDSDF*/'], which a list.

Upvotes: -1

sloth
sloth

Reputation: 101072

You can use the re module (regular expressions) to extract the parts you need from each line of text.

Example:

import re

input = ['#define ATTR_A          (HELLO +1L)     /*FSDSDF*/',
         '#define ATTR_B          (HELLO +2L)     /*FSFSSF*/']

r = re.compile(r'#define (\w*)\s*(\(.*\))')

for line in input:
    m = r.match(line)
    print '%s = %s' % (m.group(1), m.group(2))

Output:

ATTR_A = (HELLO +1L)
ATTR_B = (HELLO +2L)

Upvotes: 3

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