CODEWITHSUNDEEP
c++visual-c++macros
Bullsfan127
Bullsfan127

Reputation: 283

How do I use a macro to redefine a function in release mode?

Using C++, I need a macro that will replace a function to do nothing if it is running in release mode. So, in debug mode the function will be executed, but in release mode it will not.

Something like this:

static void foo(int,int)

#ifdef NDEBUG
#define foo(x,y)
#endif

...and the function body is defined in a separate .cpp file and is part of a class, which is why I think this isn't working?

actual code..

header

static void ValidateInput(const SeriesID *CurrentSeries, const AEnum_TT_TICK_ROUND& roundType = TT_TICK_ROUND_NONE);

.cpp

void TTBaseTick::ValidateInput(const SeriesID *CurrentSeries, const AEnum_TT_TICK_ROUND& roundType)
{
#ifndef _DEBUG
if (!CurrentSeries)
{
  throw TTTick::Ex(TTTick::SeriesNull);
}
else if (CurrentSeries->precision <= 0)
{
    throw TTTick::Ex(TTTick::PrecisionInvalid);
}
else if(!roundType.IsValidValue(roundType))
{
    throw TTTick::Ex(TTTick::InvalidParam);
}
#endif
}

Upvotes: 2

Views: 1706

Answers (2)

Ragesh Chakkadath
Ragesh Chakkadath

Reputation: 1531

static void foo(int,int); // declaration



// Definition in your cpp file.
void foo( int x, int y )
{
#ifndef NDEBUG
    // Code for debug mode
#endif
}

Upvotes: 5

Ned Batchelder
Ned Batchelder

Reputation: 375764

static void foo_(int, int);

#ifdef NDEBUG
#define foo(x,y)
#else
#define foo(x,y)   foo_(x,y)
#endif

Upvotes: 4

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