CODEWITHSUNDEEP
java
temcheg
temcheg

Reputation: 15

dynamically creating objects

I have a method that receives an array of strings and I need to create objects with appropriate names.

For example:

public class temp {    
   public static void main(String[] args){

    String[] a=new String[3];
    a[0]="first";
    a[1]="second";
    a[2]="third";
    createObjects(a);

   }
   public static void createObjects(String[] s)
   {
    //I want to have integers with same names
    int s[0],s[1],s[2];
   }
}

If I receive ("one","two") I must create:

Object one;
Object two;

If I receive ("boy","girl") I must create:

Object boy;
Object girl;

Any help would be appreciated.

Upvotes: 0

Views: 145

Answers (2)

amicngh
amicngh

Reputation: 7899

First create Map which contains the key as String representation of Integers.

public class Temp {

static Map<String, Integer> lMap;

static {

    lMap = new HashMap<String, Integer>();
    lMap.put("first", 1);
    lMap.put("second", 2);
    lMap.put("third", 3);
}

public static void main(String[] args) {
    Map<String, Integer> lMap = new HashMap<String, Integer>();
    String[] a = new String[3];
    a[0] = "first";
    a[1] = "second";
    a[2] = "third";

    Integer[] iArray=createObjects(a);
    for(Integer i:iArray){

        System.out.println(i);
    }

}

public static Integer[] createObjects(String[] s) {
    // I want to have integers with same names
    Integer[] number = new Integer[s.length];
    for (int i = 0; i < s.length; i++) {
        number[i] = lMap.get(s[i]);
    }
    return number;
}

}

Upvotes: 0

vainolo
vainolo

Reputation: 6987

Can't do that in java. You can instead create a Map who's keys are the strings and the values are the objects.

Upvotes: 7

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