Reputation: 599
I'm trying to get the Employee with the highest sales
Employee DeptNo Date Sales
Chris 2 2012/1/1 1000
Joe 1 2012/1/1 900
Arthur 3 2012/1/1 1100
Chris 2 2012/3/1 1200
Joe 1 2012/2/1 1500
Arthur 3 2010/2/1 1200
Joe 1 2010/3/1 900
Arthur 3 2010/3/1 1100
Arthur 3 2010/4/1 1200
Joe 1 2012/4/1 1500
Chris 2 2010/4/1 1800
I've tried using two subqueries, and then comparing them together to find the higher value
SELECT c1.Employee,
c1.TOTAL_SALES
FROM (SELECT Employee,
Sum(sales) AS TOTAL_SALES
FROM EmployeeSales
GROUP BY Employee) c1,
(SELECT Employee,
Sum(sales) AS TOTAL_SALES
FROM EmployeeSales
GROUP BY Employee) c2
WHERE ( c1.TOTAL_SALES > c2.TOTAL_SALES
AND c1.Employee > c2.Employee )
But the resulting query gives me two rows of
Employee TOTAL_SALES
joe 4800
joe 4800
What am I doing wrong?
Upvotes: 0
Views: 152
Reputation: 645
I would use a CTE.
;With [CTE] as (
Select
[Employee]
,sum([Sales]) as [Total_Sales]
,Row_Number()
Over(order by sum([sales]) Desc) as [RN]
From [EmployeeSales]
Group by [Employee]
)
Select
[Employee]
,[Total_Sales]
From [CTE]
Where [RN] = 1
Example of working code SQL Fiddle: http://sqlfiddle.com/#!3/bd772/2
Upvotes: 2
Reputation: 58
you can use CTE for that
WITH CTE AS ( select employee , sum(sales) as sales, ROW_NUMBER() OVER (PARTITION BY employee ORDER BY sum(sales) desc) RN FROM EmployeeSales) SELECT employee , sales FROM CTE WHERE RN =1
Upvotes: 0
Reputation: 7184
To return all employees with the highest total sales, you can use SQL Server's proprietary TOP WITH TIES:
SELECT TOP (1) WITH TIES name, SUM(sales) as total_sales
FROM employees
GROUP BY name
ORDER BY SUM(sales) DESC
Upvotes: 1
Reputation: 51
I would use a window partition
select * from
(
select
employee
, sum(sales) as sales
, row_number() over
(
order by sum(sales) desc
) as rank
from EmployeeSales
group by employee
) tmp
where tmp.rank = 1
And I agree with what someone said (Shawn) about having an employeeID and group by that for this, rather than the name.
(I removed the partition from the row_number() call as it is not needed for this)
Upvotes: 0
Reputation: 3379
SELECT name, SUM(sales) as total_sales
FROM employees
GROUP BY name
ORDER by total_sales DESC
LIMIT 1;
A better solution is to group by an employee id so we are sure they are the same person. Since there can be two Chris's.
Upvotes: 0