CODEWITHSUNDEEP
regexactionscript-3replace
iND
iND

Reputation: 2649

Like masked text, how to fill placeholders with text, and remove text to get back to placeholders?

I would like to be able to merge two (maybe three) strings as shown below. Is this possible using a regex? (The base language I am using is Actionscript 3.0, but I can work with a more generic regex solution.)

The idea is that XYZ (non-dash) chars are fixed in place, with the dashes getting replaced with the new chars, as needed. Any additions are added as if a stack which skips around the fixed chars. I imagine using a 3rd string: ---XYZ--- to maintain the placeholders.

Re to comments

Masked text input is what I am looking for, but adding from the right rather than the left. The underscores represent placeholders for added chars. They will actually be seen on screen (unless replaced, of course).

An extensive example:

Preparation: set the string length: ---------

Preparation: set the fixed: ---XYZ---

Add char: ---XYZ--a

Add char: ---XYZ-ab

Add char: ---XYZabc

Add char: --aXYZbcd

Add char: -abXYZcde

Add char: abcXYZdef

Remove char: -abXYZcde

Remove char: --aXYZbcd

Remove char: ---XYZabc

Add multiple chars: abcXYZmno

Remove multiple chars: ---XYZabc

ANSWER

Based on @Charmander's suggestion, here is a complete example:

var carr:Array = [];

function fillMaskChars(maskText:String, chars:String, pop:Boolean = false):String
{
    var maskLen:int = maskText.match(/-/g).length;

    if (pop)
    {
        carr.pop();
    }
    else if (carr.length < maskLen)
    {
        carr = carr.concat(chars.split('', maskLen - carr.length));
    }

    if (carr.length == 0)
    {
        return maskText;
    }

    var i = carr.length - maskLen - 1;

    return maskText.replace(/-/g, function()
        {
            return carr[++i] || '-';
        });
}

Some tests:

var characters:String = "oed";
var curMask:String = "--W-RK---";

var outText:String = maskChars(curMask, characters);
trace(outText);

characters = "!";
outText = maskChars(curMask, characters);
trace(outText);

characters = "abcdefghij";
outText = maskChars(curMask, characters);
trace(outText);

outText = maskChars(curMask, "", true);
trace(outText);

outText = maskChars(curMask, "", true);
trace(outText);

outText = maskChars(curMask, "", true);
trace(outText);

outText = maskChars(curMask, "", true);
trace(outText);

Upvotes: 0

Views: 315

Answers (2)

user1479055
user1479055

Reputation:

I think you will find an array more appropriate. I'm afraid I have no experience in ActionScript, but it should not be difficult to translate from JavaScript.

function fillMaskWithCharacters(mask, characters) {
    var masked = mask.match(/-/g).length;
    var i = 0;

    return mask.replace(/-/g, function() {
        return characters[--i + masked] || '-';
    });
}

It is passed an array of characters, which you may manipulate as necessary. For example:

fillMaskWithCharacters('--w-rk---', ['!', 'd', 'e', 'o']); // "--worked!"

Upvotes: 1

Sidrich2009
Sidrich2009

Reputation: 560

I dont really understand why that should be very usful, but i guess this can be done with replace substring and lastindexof

var myChars:String = _abXYZcd;
var seperator:String = XYZ;

var stringToAdd:String = ee;

var pos:int = _myChars.lastIndexOf(seperator);
var newString = myChars.substring(0, pos) + myChars.substring( (pos+seperator.length), myChars.length)
newString += seperator;
newString += stringToAdd;

but i think it would be more useful to use an array or something. like. Also i dont get if there should be limited characters, in that case all positions for replace and substring can be calculated only once... i didnt test it but i think you get the idea.

Upvotes: 0

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