CODEWITHSUNDEEP
phpjavascriptajax
dabious
dabious

Reputation: 967

Load .php page into a div Ajax and Javascript

(I am pretty new to all this.) I have a page where the user can click between different sorting methods of user posts. Depending on which they click the content shown will correspond. 

function newContent()
{
  $.ajax({
      url: 'ajax/newcontent.php',
      success: function() 
      {
            $("#content_div").empty().load("ajax/newcontent.php");
      }

      });
}

This is what I have now. But instead of loading the code from the .php page into the #content_box, the #content_box just goes blank.

Any help would be awesome!

EDIT ** changed #content_dov to #content_div - whoops

Upvotes: 2

Views: 10808

Answers (2)

Joyce Babu
Joyce Babu

Reputation: 20654

Why are you using two ajax requests? You just need to use

$("#content_dov").load("ajax/newcontent.php");

The full code is

function newContent()
{
    $("#content_dov").load("ajax/newcontent.php");
}

Upvotes: 5

Rab
Rab

Reputation: 35572

function newContent()
{
  $.ajax({
      url: 'ajax/newcontent.php',
      success: function(data) 
      {
            $("#content_dov").html(data);
      }

      });
}

Upvotes: 3

Related Questions