CODEWITHSUNDEEP
jqueryajaxparallel-processingjquery-deferredsequential
Jader Dias
Jader Dias

Reputation: 90465

How to make all AJAX calls sequential?

I use jQuery. And I don't want parallel AJAX calls on my application, each call must wait the previous before starting. How to implement it? There is any helper?

UPDATE If there is any synchronous version of the XMLHttpRequest or jQuery.post I would like to know. But sequential != synchronous, and I would like an asynchronous and sequential solution.

Upvotes: 30

Views: 47499

Answers (12)

jfriend00
jfriend00

Reputation: 707198

The modern way of sequencing jQuery asynchronous operations is to use the promises they already return and the flow control that promises support and this is not currently shown in any of the other answers here from prior years.

For example, let's suppose you wanted to load several scripts with $.getScript(), but the scripts must be loaded sequentially so the second one doesn't load/run until the first has finished and so on and you want to know when they are all done. You can directly use the promise that $.getScript() already returns. For simplicity, you can await that promise in a for loop like this:

async function loadScripts(scriptsToLoad) {
    for (const src of scriptsToLoad) {
        await $.getScript(src);
    }
}

loadScripts([url1, url2, url3]).then(() => {
    console.log("all done loading scripts");
}).catch(err => {
    console.log(err);
});

Since all jQuery Ajax-related asynchronous operations now return promises (and have for many years now), you can extend this concept to any of jQuery's Ajax-related operations.

Also, note that all the other attempts in other answers here to wrap a jQuery operation in a new promise or in a jQuery deferred are obsolete and considered a promise anti-pattern because when the operation itself already returns a promise, you can just use that promise directly without trying to wrap it in your own new promise.

Upvotes: 2

Muthu Kumar
Muthu Kumar

Reputation: 480

You can use promise to make ajax calls sequential. Using Array push and pop promise method, sequential ajax calls will be lot easier.

var promises = [Promise.resolve()];

function methodThatReturnsAPromise(id) {
  return new Promise((resolve, reject) => {
    $.ajax({
      url: 'https://jsonplaceholder.typicode.com/todos/'+id,
      dataType:'json',
      success: function(data)
      {
        console.log("Ajax Request Id"+id);
        console.log(data);
        resolve();
      }
    });
  });
} 

function pushPromise(id)
{
  promises.push(promises.pop().then(function(){
    return methodThatReturnsAPromise(id)}));
}


pushPromise(1);
pushPromise(3);
pushPromise(2);

Upvotes: 1

Rm558
Rm558

Reputation: 4994

(async () => { 
  for(f of ['1.json','2.json','3.json']){
    var json = await $.getJSON(f);
    console.log(json)
 };
})()
  1. requests 3 json files with jQuery ajax calls
  2. process in sequence (not in parallel) with await
  3. works in Chrome/Firefox/Edge (as of 1/30/2018)

more at MDN

Upvotes: 5

kamelkev
kamelkev

Reputation: 1156

sequential != synchronous, and I would like an asynchronous and sequential solution

Synchronous execution generally means "using the same clock", while sequential execution means "following in order or sequence".

For your specific use case I think both conditions must be met, as asynchronous execution implies the possibility of a non-sequential result.

Upvotes: -4

tsknakamura
tsknakamura

Reputation: 193

How about using Node.js events?

var EventEmitter = require('events').EventEmitter;
var eventEmitter = new EventEmitter();
var $ = require('jquery');

var doSomething = function (responseData) {
  var nextRequestData = {};
  // do something with responseData
  return nextRequestData;
};

// ajax requests
var request1 = $.ajax;
var request2 = $.ajax;
var requests = [request1, request2];

eventEmitter.on('next', function (i, requestData) {
  requests[i](requestData).then(
    function (responseData) {
      console.log(i, 'request completed');
      if (i+1 < requests.length) {
        var nextRequestData = doSomething(responseData);
        eventEmitter.emit('next', i+1, nextRequestData);
      }
      else {
        console.log('completed all requests');
      }
    },
    function () {
      console.log(i, 'request failed');
    }
  );
});

var data = {
  //data to send with request 1
};
eventEmitter.emit('next', 0, data);

Upvotes: -2

Todd Chaffee
Todd Chaffee

Reputation: 6824

There's a much better way to do this than using synchronous ajax calls. Jquery ajax returns a deferred so you can just use pipe chaining to make sure that each ajax call finishes before the next runs. Here's a working example with a more in depth example you can play with on jsfiddle.

// How to force async functions to execute sequentially 
// by using deferred pipe chaining.

// The master deferred.
var dfd = $.Deferred(),  // Master deferred
    dfdNext = dfd; // Next deferred in the chain
    x = 0, // Loop index
    values = [], 

    // Simulates $.ajax, but with predictable behaviour.
    // You only need to understand that higher 'value' param 
    // will finish earlier.
    simulateAjax = function (value) {
        var dfdAjax = $.Deferred();

        setTimeout(
            function () {
                dfdAjax.resolve(value);
            },
            1000 - (value * 100)
        );

        return dfdAjax.promise();
    },

    // This would be a user function that makes an ajax request.
    // In normal code you'd be using $.ajax instead of simulateAjax.
    requestAjax = function (value) {
        return simulateAjax(value);
    };

// Start the pipe chain.  You should be able to do 
// this anywhere in the program, even
// at the end,and it should still give the same results.
dfd.resolve();

// Deferred pipe chaining.
// What you want to note here is that an new 
// ajax call will not start until the previous
// ajax call is completely finished.
for (x = 1; x <= 4; x++) {

    values.push(x);

    dfdNext = dfdNext.pipe(function () {
        var value = values.shift();
        return requestAjax(value).
            done(function(response) {
                // Process the response here.

            });

    });

}

Some people have commented they have no clue what the code does. In order to understand it, you first need to understand javascript promises. I am pretty sure promises are soon to be a native javascript language feature, so that should give you a good incentive to learn.

Upvotes: 20

tomski777
tomski777

Reputation: 1

Synchronous calls aren't necessarily slower, if you have an app where AJAX calls open, posts to, then closes a socket, multiple calls to the socket don't make sense as some sockets can only handle a single connection, in which case, queuing data so its only sent when the previous AJAX call has completed means much higher data throughput.

Upvotes: -2

Joe Chung
Joe Chung

Reputation: 12123

Set the async option to false, e.g.,

$.ajax({ async: false /*, your_other_ajax_options_here */ });

Reference: Ajax/jQuery.ajax

Upvotes: 1

FWH
FWH

Reputation: 3223

Look at this: http://docs.jquery.com/Ajax/jQuery.ajax (click on the "options" tab).

But remember a synchronous call will freeze the page until the response is received, so it can't be used in a production site, because users will get mad if for any reason they have to wait 30 seconds with their browser frozen.

EDIT: ok, with your update it's clearer what you want to achieve ;)

So, your code may look like this:

    $.getJSON("http://example.com/jsoncall", function(data) {
        process(data);
        $.getJSON("http://example.com/jsoncall2", function (data) {
            processAgain(data);
            $.getJSON("http://example.com/anotherjsoncall", function(data) {
                processAgainAndAgain(data);
            });
        });
    });

This way, the second call will only be issued when the response to the first call has been received and processed, and the third call will only be issued when the response to the second call has been received and processed. This code is for getJSON but it can be adapted to $.ajax.

Upvotes: 0

Breton
Breton

Reputation: 15582

You could give narrative javascript a try http://www.neilmix.com/narrativejs/doc/

I've never used it myself though. If I wanted to do this, I would setup some kind of abstraction for chaining asynchronous actions. As others have said, the synchonous version of the ajax object blocks events from being processed while it's waiting for a response. This causes the browser to look like it's frozen until it recieves a response.

Upvotes: 1

Nosredna
Nosredna

Reputation: 86196

You have two choices that I can think of. One is to chain them through callbacks. The other is to make the calls synchronous rather than async.

Is there a reason you want them sequential? That will slow things down.

To make the call synchronous, you'll set the async option in the Ajax call to false. See the documentation at http://docs.jquery.com/Ajax/jQuery.ajax#options (click options tab to see them).

Upvotes: 6

Gab Royer
Gab Royer

Reputation: 9806

The best way you could do this is by chaining callbacks as Nosredna said. I wouldn't recommend using synchronous XMLHttpRequest as they lock your entire application.

There aren't much helper for this as far as I know, but you could do something resembling a callback FIFO.

Upvotes: 1

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