CODEWITHSUNDEEP
springspring-security
Tarun Gupta
Tarun Gupta

Reputation: 1242

Cannot find the declaration of element 'beans:beans

I am try for role based access in spring but got the following error:- 

Caused by: org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'http'.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195)
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:131)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:384)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:318)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator$XSIErrorReporter.reportError(XMLSchemaValidator.java:410)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.reportSchemaError(XMLSchemaValidator.java:3165)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.handleStartElement(XMLSchemaValidator.java:1898)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.startElement(XMLSchemaValidator.java:685)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:400)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2740)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:647)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:508)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:807)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:107)

And here is my spring-security.xml:

<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<http auto-config="true">
    <intercept-url pattern="/welcome*" access="ROLE_USER" />
    <form-login login-page="/login" default-target-url="/welcome"
        authentication-failure-url="/loginfailed" />
    <logout logout-success-url="/logout" />
</http>

<authentication-manager>
    <authentication-provider>
        <user-service>
            <user name="a" password="1" authorities="ROLE_USER" />
        </user-service>
    </authentication-provider>
</authentication-manager>

</beans:beans>

Upvotes: 2

Views: 2870

Answers (2)

Arun Kumar
Arun Kumar

Reputation: 6804

Seems, the required library files for Spring Security aren't at right place. Are you using Maven and have maven dependency of Spring Security library files in your pom.xml file?

If it is then do a maven clean-up and have a try again. Otherwise you can place Spring security library files in the class-path directly.

Upvotes: 2

Irmak Cakmak
Irmak Cakmak

Reputation: 1373

Please check if application has the necessary spring security library files in the classpath (if you are using Maven, check pom.xml file). Also, check for other Spring related xml files for syntax errors (or please post them also).

Upvotes: 0

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