CODEWITHSUNDEEP
iosobjective-cxcode
user578386
user578386

Reputation: 1061

how to open the url in safari not in webview

I want to open an url in safari, outisde the app and not in webview.

I implemented the UIWebViewDelegate but I am still not able to open the url. Basically I am not able to click the url.

Below is the code:

-(void)newView:(NSString *)title Description:(NSString *)desc URL:(NSString *)url{
    webView =[[UIWebView alloc]initWithFrame:CGRectMake(15, 17, 190, 190)];
    webView.backgroundColor=[UIColor clearColor];
    webView.delegate=self;
    webView.opaque = NO;
    [webView loadHTMLString:[NSString stringWithFormat:@"<html><body p style='color:white' text=\"#FFFFFF\" face=\"Bookman Old Style, Book Antiqua, Garamond\" size=\"5\">%@ %@</body></html>", desc,url] baseURL:nil];

    v = [[HUDView alloc] initWithFrame:CGRectMake(60, 70, 220, 220)];

    cancelButton = [UIButton buttonWithType:UIButtonTypeCustom];
    cancelButton.frame = CGRectMake(0, 0, 30, 30);
    [cancelButton setBackgroundImage:[UIImage imageNamed:@"closebox.png"] forState:UIControlStateNormal];
    [cancelButton addTarget:self action:@selector(cancelButtonPressed) forControlEvents:UIControlEventTouchUpInside];
    [v addSubview:cancelButton];
    [v addSubview:webView];
    [self.view addSubview:v];  
}

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
    if ( inType == UIWebViewNavigationTypeLinkClicked ) {
        [[UIApplication sharedApplication] openURL:[inRequest URL]];
        return NO;
    }

    return YES;
}

Upvotes: 22

Views: 55187

Answers (10)

Charlie S
Charlie S

Reputation: 4604

Swift 3 (iOS 10+):

if let url = URL(string: "http://www.seligmanventures.com") {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Upvotes: 0

George
George

Reputation: 4029

After reading the comments I think this is what you're looking for:

Implement this method: 

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType;

from UIWebViewDelegate and depending on that request argument you should return TRUE or FALSE. If you don't want the web view to open it, you should call:

[[UIApplication sharedApplication] openURL:request.URL];

as others mentioned and return FALSE.

Hope this helps. Cheers!

EDIT: If the links are not recognized in your web view, try this: 

[webView setDataDetectorTypes:UIDataDetectorTypeLink]

Upvotes: 43

I don&#39;t know
I don&#39;t know

Reputation: 801

I found this answer in google but I need to after opening the browser terminate my application and continue the browser.

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://google.com"] options: @{} completionHandler: nil];

in Android can do It easy to calling finish() method how can I do that

Upvotes: 1

Dharmesh Kheni
Dharmesh Kheni

Reputation: 71852

For iOS 10+

// Objective-C
UIApplication *application = [UIApplication sharedApplication];
[application openURL:URL options:@{} completionHandler:nil];

// Swift
UIApplication.shared.open(url, options: [:], completionHandler: nil)

For more info refer THIS.

Upvotes: 6

dirtsniffer
dirtsniffer

Reputation: 149

Swift and no webview way

    if let url = NSURL(string: "http://www.apple.com") {
        UIApplication.sharedApplication().openURL(url)
    }

Upvotes: 0

Bhavin Chauhan
Bhavin Chauhan

Reputation: 611

******************** Swift **********************

//MARK: Button Click on open with SafariViewController

private var urlString:String = "https://google.com"

@IBAction func openWithSafariVC(sender: AnyObject)
{

    let svc = SFSafariViewController(URL: NSURL(string: self.urlString)!)
    svc.delegate = self
    self.presentViewController(svc, animated: true, completion: nil)
}

//MARK: SafatriViewConroller Dismiss 

func safariViewControllerDidFinish(controller: SFSafariViewController)
{

    controller.dismissViewControllerAnimated(true, completion: nil)
}

Upvotes: 1

kordiseps
kordiseps

Reputation: 391

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType{

    if (![[NSString stringWithFormat:@"%@",[request URL]] containsString:@"file"] ) {
        [[UIApplication sharedApplication] openURL:[request URL]];
        return NO;
    }
    return YES;
}

I used an html file in local. In this html there is some links. If you set delegate UIWebViewDelegate and use this local html will open in your webView and the other links will open in safari
I wrote "file" because this link is "file:///Users/~/x.app/about.html" in local.

Upvotes: 2

Bijan
Bijan

Reputation: 26507

This works for me:

[[NSWorkspace sharedWorkspace] openURL: [NSURL URLWithString: @"http://www.apple.com"]];

Upvotes: 3

Obaid Maroof
Obaid Maroof

Reputation: 1579

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.google.com"]];

Upvotes: 8

Jtaylorapps
Jtaylorapps

Reputation: 5780

This answer was readily available via Google:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.apple.com"]];

Just put that in your button press or whatever event you're wanting to call it on, and then pass it a URL (replace the @"http:/www.apple.com").

Upvotes: 44

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