CODEWITHSUNDEEP
javascriptxmlajaxxmlhttprequest
Alexia Hurley
Alexia Hurley

Reputation: 85

Problems parsing XML in Javascript

I have a javascript function that makes an http_request to a php file on my server that generates an XML file (see output below). When the XML file is returned the same javascript function parses the XML (This is where my problem lies) and passes it to other functions; which do the bulk of the processing.

So far I've been unable to parse my XML document and I can't quite figure out why.

XML

<Results><!--Root-->
  <Result_Set>
    <State>State</State>
    <Cities>
      <City>City 1</City>
      <City selected="true">City 2</City>
       ...ETC...
    </Cities>
    <Zipcodes>
       <Zipcode selected="true">Zipcode 1</Zipcode
       <Zipcode>Zipcode 2</Zipcode>
        ...ETC...
    </Zipcodes>
  </Result_Set>
</Results>

Javascript

function GetZipInfo(zipcode){
    var xmlhttp;
    var x,resultSet,state,cities,zipcodes

    if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp=new XMLHttpRequest();
      }
    else{// code for IE6, IE5
         xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
      }

    xmlhttp.onreadystatechange=function(){
        if (xmlhttp.readyState==4 && xmlhttp.status==200){  

            resultSet=xmlhttp.responseXML.documentElement.getElementsByTagName("Result_Set") //Function Crashes Here

            for(x=0;x<resultSet.length;x++){
                state=resultSet[x].getElementsByTagName("State")[0].nodeValue;
                cities=resultSet[x].getElementsByTagName("Cities");
                zipcodes=resultSet[x].getElementsByTagName("Zipcodes");

                selectState(state)
                xmlDropdown(cities, "City", "Cities")
                xmlDropdown(zipcodes, "Zipcode", "Zipcodes")
            }
        }
    }   
    xmlhttp.open("GET","GetZipInfo.php?Zipcode="+zipcode,true);
    xmlhttp.send();
}

I have never parsed an XML document in ANY language before, so I think it's safe to say that I'm completely lost as to what's wrong.

Thank you in advance!

EDIT: It turns out that my response is coming back as responseText instead of responseXML

responseText

I am using php to create the XML page:

header("Content-Type: text/plain");
//Create the DOM
echo $xmlDoc->saveXML()

Still unsure why it's not returning as XML. Could it have something to do with echo $xmlDoc->saveXML()?

Edit: I agree with several comments that my problem is with my header in the XML file. I added the line "alert(xmlhttp.responseText)" to my code. Which displays:

<?xml version="1.0"?>
<!--The Contents of my XML file-->

Does the encoding type need to be set for this to work correctly. And if so, how can I modify my PHP code (see above) to insert that encoding?

Upvotes: 0

Views: 1848

Answers (2)

Bergi
Bergi

Reputation: 665546

The MIME type of your response should be text/xml, or something ending with +xml (RFC 3023).

Also, you should add a XML declaration before the first line.

And last, but not least, although getElementsByTagName is available on all elements in HTML documents, you should use document.getElementsByTagName in XML documents:

var resultSet = xmlhttp.responseXML.getElementsByTagName("Result_Set");

Upvotes: 1

Jordizle
Jordizle

Reputation: 252

At the top of your code your missing :

<?xml version="1.0" encoding="UTF-8" ?>

Also missing ';' after these lines :

selectState(state)
xmlDropdown(cities, "City", "Cities")
xmlDropdown(zipcodes, "Zipcode", "Zipcodes")

In XML also missing '>' after :

</Zipcode

Upvotes: 0

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