CODEWITHSUNDEEP
sqloracle-database
Ray J Tong
Ray J Tong

Reputation: 897

How to query GROUP BY Month in a Year

I am using Oracle SQL Developer. I essentially have a table of pictures that holds the columns:

[DATE_CREATED(date), NUM_of_PICTURES(int)]

and if I do a select *, I would get an output similar to:

01-May-12    12
02-May-12    15
03-May-12    09
...
...
01-Jun-12    20
...
etc.

I am trying to aggregate these sums of pictures into MONTHLY numbers instead of DAILY.

I've tried doing something like:

select Month(DATE_CREATED), sum(Num_of_Pictures))
from pictures_table
group by Month(DATE_CREATED);

This outputs an error:

ORA-00904: "MONTH": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 5 Column: 9

Do I have the Month function wrong?

Upvotes: 65

Views: 277317

Answers (5)

Sam MirzaGharcheh
Sam MirzaGharcheh

Reputation: 117

I am doing like this in MSSQL

Getting Monthly Data:

 SELECT YEAR(DATE_CREATED) [Year], MONTH(DATE_CREATED) [Month], 
     DATENAME(MONTH,DATE_CREATED) [Month Name], SUM(Num_of_Pictures) [Pictures Count]
    FROM pictures_table
    GROUP BY YEAR(DATE_CREATED), MONTH(DATE_CREATED), 
     DATENAME(MONTH, DATE_CREATED)
    ORDER BY 1,2

Getting Monthly Data using PIVOT:

SELECT *
FROM (SELECT YEAR(DATE_CREATED) [Year], 
       DATENAME(MONTH, DATE_CREATED) [Month], 
       SUM(Num_of_Pictures) [Pictures Count]
      FROM pictures_table
      GROUP BY YEAR(DATE_CREATED), 
      DATENAME(MONTH, DATE_CREATED)) AS MontlySalesData
PIVOT( SUM([Pictures Count])   
    FOR Month IN ([January],[February],[March],[April],[May],
    [June],[July],[August],[September],[October],[November],
    [December])) AS MNamePivot

Upvotes: -1

Gordon Linoff
Gordon Linoff

Reputation: 1271003

I would be inclined to include the year in the output. One way:

select to_char(DATE_CREATED, 'YYYY-MM'), sum(Num_of_Pictures)
from pictures_table
group by to_char(DATE_CREATED, 'YYYY-MM')
order by 1

Another way (more standard SQL):

select extract(year from date_created) as yr, extract(month from date_created) as mon,
       sum(Num_of_Pictures)
from pictures_table
group by extract(year from date_created), extract(month from date_created)
order by yr, mon;

Remember the order by, since you presumably want these in order, and there is no guarantee about the order that rows are returned in after a group by.

Upvotes: 143

Holger Brandt
Holger Brandt

Reputation: 4354

For Oracle:

select EXTRACT(month from DATE_CREATED), sum(Num_of_Pictures)
from pictures_table
group by EXTRACT(month from DATE_CREATED);

Upvotes: 22

jaseer
jaseer

Reputation: 1

You can use:

    select FK_Items,Sum(PoiQuantity) Quantity  from PurchaseOrderItems POI
    left join PurchaseOrder PO ON po.ID_PurchaseOrder=poi.FK_PurchaseOrder
    group by FK_Items,DATEPART(MONTH, TransDate)

Upvotes: -3

Rob
Rob

Reputation: 2472

For MS SQL you can do this.

    select  CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+ 
CAST(DATEPART(YEAR, DateTyme) as VARCHAR) as 'Date' from #temp
    group by Name, CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+
 CAST(DATEPART(YEAR, DateTyme) as VARCHAR)

Upvotes: -3

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