edparry
edparry

Reputation: 718

Returning child nodes of a particular type and their properties (Umbraco)

I'm trying to write some XSLT which basically should go through the following algorithm:

if child of current node is of type Accordion
    if child of Accordion node is of type AccordionItem
        take the AccordionItem's title and content and display in <div> tags
    end if
end if

It seems pretty straight forward, but the code I currently have doesn't appear to be working as it should. I must be missing something, but I can't figure out exactly what. Here's my XSLT code so far:

<xsl:for-each select="$currentPage/ancestor-or-self::Home//AccordionItem[@isDoc]">
    <div id="accordion">
        <h3><a href='#'><xsl:value-of select="accordionItemTitle"/></a></h3>
        <div><xsl:value-of select="accordionItemContent" disable-output-escaping="yes" />
        </div>
    </div>
</xsl:for-each>

Can anyone offer any suggestions as to why this wouldn't be working correctly? Thanks in advanced!

Upvotes: 1

Views: 1312

Answers (1)

Goran Mottram
Goran Mottram

Reputation: 6304

It seems that your XPath isn't quite behaving as you've defined in your algorithm and is navigating to the node of type Home, is that intended?

If not, try modifying the XPath to the following:

<xsl:for-each select="$currentPage/Accordion/AccordionItem[@isDoc]">

Upvotes: 2

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