Reputation: 6040
public class Common {
public synchronized void synchronizedMethod1() {
System.out.println("synchronizedMethod1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("synchronizedMethod1 done");
}
public void method1() {
System.out.println("Method 1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Method 1 done");
}
}
public class MyThread extends Thread {
private int id = 0;
private Common common;
public MyThread(String name, int no, Common object) {
super(name);
common = object;
id = no;
}
public void run() {
System.out.println("Running Thread" + this.getName());
try {
if (id == 0) {
common.synchronizedMethod1();
} else {
common.method1();
}
} catch (Exception e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
Common c = new Common();
MyThread t1 = new MyThread("MyThread-1", 0, c);
MyThread t2 = new MyThread("MyThread-2", 1, c);
t1.start();
t2.start();
}
}
Output:
Running ThreadMyThread-1
synchronizedMethod1 called
Running ThreadMyThread-2
Method 1 called
synchronizedMethod1 done
Method 1 done
I would like to find a way to prevent method1() from running when i called synchronizedMethod1. Unless I'm mistaken all methods are called and Java compiles them during and before runtime regardless if it's synchronized or not.
Should i have used a Lock object instead and/or not also make method1() a synchronized method?
Upvotes: 0
Views: 1635
Reputation: 20442
If you want method1
and synchronizedMethod1
to be mutually exclusive then you need to guard them with the same lock. Whether this is using a Lock
or simply calling synchronize
on the same Object instance, the outcome is roughly the same.
On the off chance you want multiple threads to be allowed to execute method1
but not when synchronizedMethod1
is being invoked, you need a ReadWriteLock
to accomplish that.
public class Common {
ReadWriteLock rwLock = new ReentrantReadWriteLock();
public void synchronizedMethod1() {
rwLock.writeLock().lock();
try {
System.out.println("synchronizedMethod1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("synchronizedMethod1 done");
} finally {
rwLock.writeLock().unlock();
}
}
public void method1() {
rwLock.readLock().lock();
try {
System.out.println("Method 1 called");
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Method 1 done");
} finally {
rwLock.readLock().unlock();
}
}
}
Upvotes: 0
Reputation: 116858
I would like to find a way to prevent method1() from running when i called synchronizedMethod1
The easiest way to do this is to make method1()
also be synchronized
. This will mean that both methods will cause a lock on the instance of Common
that they are calling. Only one thread will be able to either be calling synchronizedMethod1()
or method1()
.
Unless I'm mistaken all methods are called and Java compiles them during and before runtime regardless if it's synchronized or not.
I don't understand this question. You really should not have to worry about the compilation or optimization phase of the JVM.
Should i have used a Lock object instead?
Usually making a method synchronized
is considered not as good as using a private final
lock object. Lock objects just allow you to be more fine grained in your locks. For example, with method locking, log messages and other statements that do not need protection will be synchronized
as well. But if the goal is to lock the entire method then synchronizing the methods is fine.
Upvotes: 1