CODEWITHSUNDEEP
mysql
dbj44
dbj44

Reputation: 1998

Batting average MySQL query

You may need some knowledge of cricket to help with this one. Given the following table, would this query produce this result?

Table: batsmen
batsmanname | runsscored | howout
Colin       | 10         | bowled
Colin       | 20         | caught
Steve       | 10         | bowled
Steve       | 20         | not out

SELECT batsmanname, SUM(runsscored) / COUNT(howout) AS battingavg
FROM batsmen 
WHERE howout <> 'not out' 
GROUP BY batsmananme

Result:
batsmanname | battingavg
Colin       | 15
Steve       | 30

Upvotes: 0

Views: 383

Answers (1)

Taryn
Taryn

Reputation: 247810

This should produce the results that you want:

SELECT b1.name, SUM(b1.runsscored) / b2.NumOut as bat_avg
FROM batsmen b1
INNER JOIN
(
  select name, COUNT(howout) as NumOut
  from batsmen
  WHERE howout <> 'not out' 
  GROUP BY name
) b2
  ON b1.name = b2.name
GROUP BY b1.name

See SQL Fiddle with demo

Upvotes: 1

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